字符串排序

def strPaiXu(p):
    s = ''
    a = [ord(i) for i in p]
   #a = list(map(ord,p)) a.sort() p
= [chr(i) for i in a] for i in p: s += i return s

 

posted @ 2017-01-03 20:32  疯陈演义  阅读(118)  评论(0编辑  收藏  举报