让你瞬间萌比的35个python小技巧

今天在看python算法的时候,看到一篇关于python的小技巧。瞬间萌比了,原来python也可以这样玩,太神奇了。萌比的是原来这么简单的东西自己都不知道,虽然会写。废话不多说了,开始上菜。

1、拆箱

>>> a,b,c = 1,2,3
>>> a,b,c
(1, 2, 3)
>>> a,b,c = [1,2,3]
>>> a,b,c
(1, 2, 3)
>>> a,b,c = (2 * i + 1 for i in range(3))
>>> a,b,c
(1, 3, 5)
>>> a,(b,c),d = [1,(2,3),4]
>>> a
1
>>> b
2
>>> c
3
>>> d
4

2、拆箱变量交换

>>> a,b,c = 1,2,3
>>> a,b,c = b,c,a
>>> a,b,c
(2, 3, 1)

3、扩展拆箱(只兼容python3)

>>> a, *b, c = [1, 2, 3, 4, 5]
>>> a
1
>>> b
[2, 3, 4]
>>> c
5

4、负数索引

>>> a = [1,2,3,4,5,6,7,8,9,0]
>>> a[-1]
0
>>> a[-3]
8

5、切割列表

>>> a = [1,2,3,4,5,6,7,8,9,0]
>>> a[2:6]
[3, 4, 5, 6]

6、负数索引切割列表

>>> a = [1,2,3,4,5,6,7,8,9,]
>>> a[-4:-3]
[6]
>>> a[-4:-7]
[]
>>> a[-7:-4]
[3, 4, 5]

7、指定不长切割列表

>>> a=[1,2,3,4,5,6,7,8,9,0]
>>> a[::3]
[1, 4, 7, 0]
>>> a[::2]
[1, 3, 5, 7, 9]
>>> a[2:8:2]
[3, 5, 7]
>>> a[:2:8]
[1]

8、负数步长切割列表

>>> a=[1,2,3,4,5,6,7,8,9,10,11,12,13,14]
>>> a[::-3]
[14, 11, 8, 5, 2]
>>> a[::-5]
[14, 9, 4]
>>> a[-2:-3:-4]
[13]

9、列表切割赋值

>>> a=[1,2,3,4,5]
>>> a[2:3]
[3]
>>> a[2:3]=[0,0]
>>> a
[1, 2, 0, 0, 4, 5]
>>> a[1:1]
[]
>>> a[1:1]=[8,9]
>>> a
[1, 8, 9, 2, 0, 0, 4, 5]
>>> a[1:-1]
[8, 9, 2, 0, 0, 4]
>>> a[1:-1]=[]
>>> a
[1, 5]

10、命名列表切割方式

>>> a=[1,2,3,4,5]
>>> LASTTHREE = slice(-3,None)
>>> LASTTHREE
slice(-3, None, None)
>>> a[LASTTHREE]
[3, 4, 5]

11、列表以及迭代器的压缩和解压

>>> a=[1,2,3,4,5]
>>> b=['a', 'b', 'c']
>>> z=zip(a,b)
>>> z
[(1, 'a'), (2, 'b'), (3, 'c')]
>>> zip(*z)
[(1, 2, 3), ('a', 'b', 'c')]

12、列表相邻元素压缩器

>>> a=[1,2,3,4,5]
>>> zip(*([iter(a)] * 2))
[(1, 2), (3, 4)]
>>> a=[1,2,3,4,5,6]
>>> zip(*([iter(a)] * 2))
[(1, 2), (3, 4), (5, 6)]
>>> group_adjacent=lambda a, k:zip(*([iter(a)] * k))
>>> group_adjacent(a,3)
[(1, 2, 3), (4, 5, 6)]
>>> group_adjacent(a,2)
[(1, 2), (3, 4), (5, 6)]
>>> group_adjacent(a,1)
[(1,), (2,), (3,), (4,), (5,), (6,)]
>>> zip(a[::2], a[1::2])
[(1, 2), (3, 4), (5, 6)]
>>> zip(a[::3], a[1::3], a[2::3])
[(1, 2, 3), (4, 5, 6)]
>>> group_adjacent=lambda a, k:zip(*(a[i::k] for i in range(k)))
>>> group_adjacent(a, 3)                                    
[(1, 2, 3), (4, 5, 6)]
>>> group_adjacent(a, 2)
[(1, 2), (3, 4), (5, 6)]
>>> group_adjacent(a, 1)
[(1,), (2,), (3,), (4,), (5,), (6,)]

13、在列表中用压缩器和迭代器滑动取值窗口

>>> def n_grams(a,n):
...     z=[iter(a[i:]) for i in range(n)]
...     return zip(*z)
... 
>>> a=[1,2,3,4,5,6,7,8,9]
>>> n_grams(a,3)
[(1, 2, 3), (2, 3, 4), (3, 4, 5), (4, 5, 6), (5, 6, 7), (6, 7, 8), (7, 8, 9)]
>>> n_grams(a,2)
[(1, 2), (2, 3), (3, 4), (4, 5), (5, 6), (6, 7), (7, 8), (8, 9)]
>>> n_grams(a,4)
[(1, 2, 3, 4), (2, 3, 4, 5), (3, 4, 5, 6), (4, 5, 6, 7), (5, 6, 7, 8), (6, 7, 8, 9)]

14、用压缩器反转字典

>>> m={'a':1, 'b':2,'c':3,'d':4}
>>> m.items()
[('a', 1), ('c', 3), ('b', 2), ('d', 4)]
>>> zip(m.values(), m.keys())
[(1, 'a'), (3, 'c'), (2, 'b'), (4, 'd')]
>>> mi=dict(zip(m.values(), m.keys()))
>>> mi
{1: 'a', 2: 'b', 3: 'c', 4: 'd'}

15、列表展开

>>> import itertools
>>> a = [[1, 2], [3, 4], [5, 6]]
>>> list(itertools.chain.from_iterable(a))
[1, 2, 3, 4, 5, 6]
>>> sum(a, [])
[1, 2, 3, 4, 5, 6]
>>> [x for l in a for x in l]
[1, 2, 3, 4, 5, 6]
>>> a = [[[1, 2], [3, 4]], [[5, 6], [7, 8]]]
>>> [x for l1 in a for l2 in l1 for x in l2]
[1, 2, 3, 4, 5, 6, 7, 8]
>>> a = [1, 2, [3, 4], [[5, 6], [7, 8]]]
>>> flatten = lambda x: [y for l in x for y in flatten(l)] if type(x) is list else [x]
>>> flatten(a)
[1, 2, 3, 4, 5, 6, 7, 8]

16、生成器表达式

>>> g=(x ** 2 for x in xrange(10))
>>> next(g)
0
>>> next(g)
1
>>> next(g)
4
>>> next(g)
9
>>> sum(x ** 3 for x in xrange(10))
2025
>>> sum(x ** 3 for x in xrange(10) if x % 3 == 1)
408

17、字典推导

>>> m = {x: x ** 2 for x in range(5)}
>>> m
{0: 0, 1: 1, 2: 4, 3: 9, 4: 16}
>>> m = {x: 'B' + str(x) for x in range(10)}
>>> m
{0: 'B0', 1: 'B1', 2: 'B2', 3: 'B3', 4: 'B4', 5: 'B5', 6: 'B6', 7: 'B7', 8: 'B8', 9: 'B9'}

18、用字典推导反转字典

>>> m={'a':1,'b':2,'c':3,'d':4}
>>> m
{'a': 1, 'c': 3, 'b': 2, 'd': 4}
>>> {v:k for k,v in m.items()}
{1: 'a', 2: 'b', 3: 'c', 4: 'd'}

19、命名元组

>>> import collections
>>> point = collections.namedtuple('point', ['x', 'y'])
>>> p = point(x=1.0, y=2.0)
>>> p.x
1.0
>>> p.y
2.0

20、继承命名元组

>>> import collections                                      
>>> class Point(collections.namedtuple('PointBase', ['x', 'y'])):
...     __slots__ =()
...     def __add__(self, other):                         
...             return Point(x=self.x + other.x, y=self.y + other.y)
... 
>>> p = Point(x=1.0, y=2.0)
>>> q = Point(x=2.0, y=3.0)
>>> p + q
PointBase(x=3.0, y=5.0)

21、操作集合

>>> A = {1, 2, 3, 4}
>>> A
set([1, 2, 3, 4])
>>> B = {3, 4, 5, 6, 7}
>>> B
set([3, 4, 5, 6, 7])
>>> A | B
set([1, 2, 3, 4, 5, 6, 7])
>>> A & B
set([3, 4])
>>> A - B
set([1, 2])
>>> B - A
set([5, 6, 7])
>>> A ^ B
set([1, 2, 5, 6, 7])
>>> (A ^ B) == ((A - B) | (B - A))
True

22、操作多重集合

>>> A = collections.Counter([1, 2, 2])
>>> B = collections.Counter([2, 2, 3])
>>> A
Counter({2: 2, 1: 1})
>>> B
Counter({2: 2, 3: 1})
>>> A | B
Counter({2: 2, 1: 1, 3: 1})
>>> A & B
Counter({2: 2})
>>> A + B
Counter({2: 4, 1: 1, 3: 1})
>>> A - B
Counter({1: 1})
>>> B - A
Counter({3: 1})

23、统计在可迭代器中最常出现的元素

>>> A = collections.Counter([1, 1, 2, 2, 3, 3, 3, 3, 4, 5, 6, 7])
>>> A
Counter({3: 4, 1: 2, 2: 2, 4: 1, 5: 1, 6: 1, 7: 1})
>>> A.most_common(1)
[(3, 4)]
>>> A.most_common(2)
[(3, 4), (1, 2)]
>>> A.most_common(3)
[(3, 4), (1, 2), (2, 2)]

24、两端都可操作的队列

>>> Q = collections.deque()
>>> Q.append(1)
>>> Q.appendleft(2)
>>> Q.extend([3, 4])
>>> Q.extendleft([5, 6])
>>> Q
deque([6, 5, 2, 1, 3, 4])
>>> Q.pop()
4
>>> Q.popleft()
6
>>> Q
deque([5, 2, 1, 3])
>>> Q.rotate(3)
>>> Q
deque([2, 1, 3, 5])
>>> Q.rotate(-3)
>>> Q
deque([5, 2, 1, 3])

25、有最大长度的双端队列

>>> last_three = collections.deque(maxlen=3)
>>> for i in xrange(10):
...     last_three.append(i)
...     print ', '.join(str(x) for x in last_three)
...
0
0, 1
0, 1, 2
1, 2, 3
2, 3, 4
3, 4, 5
4, 5, 6
5, 6, 7
6, 7, 8
7, 8, 9

26、可排序词典

>>> m = dict((str(x), x) for x in range(10))
>>> print ', '.join(m.keys())
1, 0, 3, 2, 5, 4, 7, 6, 9, 8
>>> m = collections.OrderedDict((str(x), x) for x in range(10))
>>> print ', '.join(m.keys())
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
>>> m = collections.OrderedDict((str(x), x) for x in range(10, 0, -1))
>>> print ', '.join(m.keys())
10, 9, 8, 7, 6, 5, 4, 3, 2, 1

27、默认词典

>>> m = dict()
>>> m['a']
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
KeyError: 'a'
>>>
>>> m = collections.defaultdict(int)
>>> m['a']
0
>>> m['b']
0
>>> m = collections.defaultdict(str)
>>> m['a']
''
>>> m['b'] += 'a'
>>> m['b']
'a'
>>> m = collections.defaultdict(lambda: '[default value]')
>>> m['a']
'[default value]'
>>> m['b']
'[default value]'

28、默认字典的简单树状表达

>>> import json
>>> tree = lambda: collections.defaultdict(tree)
>>> root = tree()
>>> root['menu']['id'] = 'file'
>>> root['menu']['value'] = 'File'
>>> root['menu']['menuitems']['new']['value'] = 'New'
>>> root['menu']['menuitems']['new']['onclick'] = 'new();'
>>> root['menu']['menuitems']['open']['value'] = 'Open'
>>> root['menu']['menuitems']['open']['onclick'] = 'open();'
>>> root['menu']['menuitems']['close']['value'] = 'Close'
>>> root['menu']['menuitems']['close']['onclick'] = 'close();'
>>> print json.dumps(root, sort_keys=True, indent=4, separators=(',', ': '))
{
    "menu": {
        "id": "file",
        "menuitems": {
            "close": {
                "onclick": "close();",
                "value": "Close"
            },
            "new": {
                "onclick": "new();",
                "value": "New"
            },
            "open": {
                "onclick": "open();",
                "value": "Open"
            }
        },
        "value": "File"
    }
}

29、对象到唯一计数的映射

>>> import itertools, collections
>>> value_to_numeric_map = collections.defaultdict(itertools.count().next)
>>> value_to_numeric_map['a']
0
>>> value_to_numeric_map['b']
1
>>> value_to_numeric_map['c']
2
>>> value_to_numeric_map['a']
0
>>> value_to_numeric_map['b']
1

30、最大和最小的几个列表元素

>>> a = [random.randint(0, 100) for __ in xrange(100)]
>>> heapq.nsmallest(5, a)
[3, 3, 5, 6, 8]
>>> heapq.nlargest(5, a)
[100, 100, 99, 98, 98]

31、两个列表的笛卡尔积

>>> for p in itertools.product([1, 2, 3], [4, 5]):
(1, 4)
(1, 5)
(2, 4)
(2, 5)
(3, 4)
(3, 5)
>>> for p in itertools.product([0, 1], repeat=4):
...     print ''.join(str(x) for x in p)
...
0000
0001
0010
0011
0100
0101
0110
0111
1000
1001
1010
1011
1100
1101
1110
1111

32、列表组合和列表元素替代组合

>>> for c in itertools.combinations([1, 2, 3, 4, 5], 3):
...     print ''.join(str(x) for x in c)
...
123
124
125
134
135
145
234
235
245
345
>>> for c in itertools.combinations_with_replacement([1, 2, 3], 2):
...     print ''.join(str(x) for x in c)
...
11
12
13
22
23
33

33、列表元素排列组合

>>> for p in itertools.permutations([1, 2, 3, 4]):
...     print ''.join(str(x) for x in p)
...
1234
1243
1324
1342
1423
1432
2134
2143
2314
2341
2413
2431
3124
3142
3214
3241
3412
3421
4123
4132
4213
4231
4312
4321

34、可链接迭代器

>>> a = [1, 2, 3, 4]
>>> for p in itertools.chain(itertools.combinations(a, 2), itertools.combinations(a, 3)):
...     print p
...
(1, 2)
(1, 3)
(1, 4)
(2, 3)
(2, 4)
(3, 4)
(1, 2, 3)
(1, 2, 4)
(1, 3, 4)
(2, 3, 4)
>>> for subset in itertools.chain.from_iterable(itertools.combinations(a, n) for n in range(len(a) + 1))
...     print subset
...
()
(1,)
(2,)
(3,)
(4,)
(1, 2)
(1, 3)
(1, 4)
(2, 3)
(2, 4)
(3, 4)
(1, 2, 3)
(1, 2, 4)
(1, 3, 4)
(2, 3, 4)
(1, 2, 3, 4)

35、根据文件指定列类聚

>>> import itertools
>>> with open('contactlenses.csv', 'r') as infile:
...     data = [line.strip().split(',') for line in infile]
...
>>> data = data[1:]
>>> def print_data(rows):
...     print '\n'.join('\t'.join('{: <16}'.format(s) for s in row) for row in rows)
...
 
>>> print_data(data)
young               myope                   no                      reduced                 none
young               myope                   no                      normal                  soft
young               myope                   yes                     reduced                 none
young               myope                   yes                     normal                  hard
young               hypermetrope            no                      reduced                 none
young               hypermetrope            no                      normal                  soft
young               hypermetrope            yes                     reduced                 none
young               hypermetrope            yes                     normal                  hard
pre-presbyopic      myope                   no                      reduced                 none
pre-presbyopic      myope                   no                      normal                  soft
pre-presbyopic      myope                   yes                     reduced                 none
pre-presbyopic      myope                   yes                     normal                  hard
pre-presbyopic      hypermetrope            no                      reduced                 none
pre-presbyopic      hypermetrope            no                      normal                  soft
pre-presbyopic      hypermetrope            yes                     reduced                 none
pre-presbyopic      hypermetrope            yes                     normal                  none
presbyopic          myope                   no                      reduced                 none
presbyopic          myope                   no                      normal                  none
presbyopic          myope                   yes                     reduced                 none
presbyopic          myope                   yes                     normal                  hard
presbyopic          hypermetrope            no                      reduced                 none
presbyopic          hypermetrope            no                      normal                  soft
presbyopic          hypermetrope            yes                     reduced                 none
presbyopic          hypermetrope            yes                     normal                  none
 
>>> data.sort(key=lambda r: r[-1])
>>> for value, group in itertools.groupby(data, lambda r: r[-1]):
...     print '-----------'
...     print 'Group: ' + value
...     print_data(group)
...
-----------
Group: hard
young               myope                   yes                     normal                  hard
young               hypermetrope            yes                     normal                  hard
pre-presbyopic      myope                   yes                     normal                  hard
presbyopic          myope                   yes                     normal                  hard
-----------
Group: none
young               myope                   no                      reduced                 none
young               myope                   yes                     reduced                 none
young               hypermetrope            no                      reduced                 none
young               hypermetrope            yes                     reduced                 none
pre-presbyopic      myope                   no                      reduced                 none
pre-presbyopic      myope                   yes                     reduced                 none
pre-presbyopic      hypermetrope            no                      reduced                 none
pre-presbyopic      hypermetrope            yes                     reduced                 none
pre-presbyopic      hypermetrope            yes                     normal                  none
presbyopic          myope                   no                      reduced                 none
presbyopic          myope                   no                      normal                  none
presbyopic          myope                   yes                     reduced                 none
presbyopic          hypermetrope            no                      reduced                 none
presbyopic          hypermetrope            yes                     reduced                 none
presbyopic          hypermetrope            yes                     normal                  none
-----------
Group: soft
young               myope                   no                      normal                  soft
young               hypermetrope            no                      normal                  soft
pre-presbyopic      myope                   no                      normal                  soft
pre-presbyopic      hypermetrope            no                      normal                  soft
presbyopic          hypermetrope            no                      normal                  soft

 尊重劳动者的知识产权,请打上出处:http://python.jobbole.com/63320/

posted @ 2016-05-24 22:54  吴老二  阅读(952)  评论(1编辑  收藏  举报