Codeforces Round #174 (Div. 2)

A题  模拟题   比赛是  sb 了

 1 #include<iostream>
 2 #include<stdio.h>
 3 #include<cstring>
 4 #include<algorithm>
 5 using namespace std;
 6 
 7 int main( )
 8 {
 9     int N,res,k;
10     while( scanf("%d",&N) != EOF )
11     {
12         res = 0;
13         for( int i = 1; i < N; i++ )
14         {
15             bool fell = false; k = 1;
16             for( int j = 1; j < N-1; j++ )
17             {
18                 k *= i; k %= N;
19                 if( k == 1 )
20                 {
21                     fell = true;
22                     break;
23                 }
24             }
25             if( !fell && k*i%N == 1 )
26                res++;
27         }
28         printf("%d\n",res);
29     }
30     return 0;
31 }

B题  模拟题  关键是读懂题目

 1 #include<iostream>
 2 #include<stdio.h>
 3 #include<algorithm>
 4 #include<cstring>
 5 using namespace std;
 6 
 7 
 8 char str[212345];
 9 
10 int main( )
11 {
12     int N;
13     while( scanf("%d",&N) != EOF )
14     {
15         scanf("%s",&str);
16         int len = strlen(str);
17         int a = 0,b = 0,c = 0;
18         for( int i = 0; i < len; i++ )
19         if( str[i] == 'A') a++ ;
20         else if( str[i] == 'F')b++;
21         else if( str[i] == 'I')c++;
22         if( b == len || c >= 2 )
23         {
24             cout<<0<<endl;
25         }
26         else 
27         if( c != 0 )
28              cout<<1<<endl;
29         else cout<<a<<endl;
30     }
31     return 0;
32 }

C 题 比赛后才想出来  sb了

 1 #include<iostream>
 2 #include<stdio.h>
 3 #include<cstring>
 4 #include<algorithm>
 5 using namespace std;
 6 
 7 long long arr[212345],cnt[212345];
 8 
 9 int main( )
10 {
11     int N,k,t;
12     long long a,b,ans,res;
13     scanf("%d",&N);
14     memset(cnt,0,sizeof(cnt));
15     res = 0; ans = 1;k = 1; arr[1] = 0;
16     while( N-- )
17     {
18         scanf("%d",&t);
19         if( t == 1 )
20         {
21             scanf("%I64d%I64d",&a,&b);
22                res += (a*b);
23             cnt[a] += b;
24             printf("%.6lf\n",double(res*1.0/ans*1.0));
25             continue;
26         }
27         if( t == 2 )
28         {
29             scanf("%I64d",&arr[++k]);
30                res += arr[k];
31             ans++;
32             printf("%.6lf\n",double(res*1.0/ans*1.0));
33             continue;
34         }
35         if( t == 3 && k >= 2 )
36         {
37             res = res - arr[k] - cnt[k];
38             cnt[k-1] += cnt[k]; cnt[k] = 0;
39             ans--;
40               k--;
41             printf("%.6lf\n",double(res*1.0/ans*1.0));
42         }
43     }
44     return 0;
45 }

D题  记忆化搜索  关键是 记住三个状态

 1 #include<iostream>
 2 #include<stdio.h>
 3 #include<cstring>
 4 #include<algorithm>
 5 using namespace std;
 6 
 7 long long arr[212345];
 8 long long num[212345][3],N,ans,res;
 9 
10 bool  stu[212345][3];
11 bool  vis[212345][3];
12 
13 long long DFS( long long x,long long y,int tab )
14 {
15     if( x <= 0 || x > N ) { res = y;  return ans = 0; }
16     if(   vis[x][tab]   )
17     {
18         if( num[x][tab] == -1 )  return res = -1;
19                res = num[x][tab] + y;
20         return ans = num[x][tab];
21     }
22     if( stu[x][tab] ){ res = -1;vis[x][tab] = true; num[x][tab] = -1; return -1;}
23           stu[x][tab] = true;
24     if( !tab )
25     {
26         long long t = DFS( x-arr[x],y+arr[x],1 );
27             vis[x][0] = true;
28         if( t != -1 ) ans += arr[x];
29         return        num[x][0] = ans;
30     }
31     else
32     {
33         long long t = DFS( x+arr[x],y+arr[x],0 );
34             vis[x][1] = true;
35         if( t != -1 ) ans += arr[x];
36         return        num[x][1] = ans;
37     }
38     return 0;
39 }
40 
41 int main( )
42 {
43      int i,x,y;
44      scanf("%I64d",&N);
45      for( i = 2; i <= N; i++ )
46         scanf("%I64d",&arr[i]);
47      memset( vis,false,sizeof(vis) );
48      memset( stu,false,sizeof(stu) );
49      memset( num,0,sizeof(num) );
50      for( i = 1; i < N; i++ )
51      {
52          arr[1] = i; x = 1 + i; y = i;ans = -1; DFS( x,y,0 );
53          printf("%I64d\n",res);
54      }
55     return 0;
56 }

E题   好题,,,看来N 篇解题报告才出来  还有 一个就是  题目真的很坑啊!  可能是没有读通题目,后来把自己代码换了一个地方就过了;原理没有改变;真是  坑爹的;

 1 #include<iostream>
 2 #include<stdio.h>
 3 #include<cstring>
 4 #include<algorithm>
 5 using namespace std;
 6 
 7 const int inf = 1000000007;
 8 int  next[330],pre[330],arr[330],stu[440],h[330],va,wa,k;
 9 int  dp[212345];
10 int  vis[330],vic[330];
11 bool fell;
12 
13 void dfs(int u)
14 {
15     if( pre[u] == 0)
16     {
17         vis[u] = 2;
18         h[u] = 1;
19         return;
20     }
21     if( vis[pre[u]] == 1 )
22     {
23         fell = false;
24         return;
25     }
26     vis[u] = 1;
27     if( vis[pre[u]] == 0 )
28         dfs( pre[u] );
29     if ( !fell ) return;
30     h[u] = h[pre[u]] + 1;
31     vis[u] = 2;
32 }
33 
34 void DFS( int sta )
35 {
36     if( vic[sta] ) return ;
37     va += arr[sta];
38     stu[sta] = va;
39     vic[sta] = true;
40     if(  pre[sta] && next[pre[sta]] == sta )  DFS( pre[sta] );
41     return ;
42 }
43 
44 int main( )
45 {
46     int N,M,x,y,T;
47     while( scanf("%d%d%d",&N,&M,&T) != EOF )
48     {
49         for( int i = 1; i <= N; i++ )
50          scanf("%d",&arr[i]);
51         memset( pre,0,sizeof(pre) );
52         memset( next,0,sizeof(next) );
53         for( int i = 1; i <= M; i++ )
54         {
55             scanf("%d%d",&x,&y);
56             next[y] = x;pre[x] = y;
57         }
58         fell = true;
59         memset( vis,0,sizeof(vis) );
60         memset( h,0,sizeof(h));
61         for (int i = 1; i <= N; i++)
62         if( vis[i] == 0 && fell ) dfs(i);
63         if (fell)
64         {
65             for ( int i = 1; i <= N; i++)
66             {
67                  T -= ( h[i] - 1) * arr[i];
68                 if (T < 0) break;
69             }
70             if (T < 0) fell = false;
71         }
72 
73         if (!fell)
74         {
75             printf("0\n");
76             continue;
77         }
78         memset( vic,false,sizeof(vic) );
79         for( int i = 1; i <= N; i++ )
80         if( next[i] == 0 )
81         {
82             va = 0; DFS( i );
83         }
84 
85         memset( dp,0,sizeof(dp) );
86         dp[0] = 1;
87         for( int i = 1; i <= N; i++ )
88         {
89             for( int j = stu[i]; j <= T; j++ )
90             {
91                 long long t = (dp[j] + dp[j-stu[i]]);
92                 if( t >= inf ) t -= inf;
93                 dp[j] = t;
94             }
95         }
96         printf("%d\n",dp[T]);
97     }
98     return 0;
99 }

 

posted on 2013-03-26 22:15  浪舟  阅读(215)  评论(0编辑  收藏  举报

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