HDOJ 4415 Assassin’s Creed

#include<iostream>
#include<stdio.h>
#include<algorithm>
#include<cstring>
using namespace std;

struct point
{
    int A,B;
    bool vis;
} node[100005];

bool cmp( point a,point b )
{
    return a.A < b.A;
}

int main(  )
{
    int i,j,k,t,T,cas,n,m,ans,count,sum1,sum2,b1,b2;
    scanf("%d",&T);
    for( cas = 1; cas <= T; cas++ )
    {
        scanf("%d%d",&n,&m);
        for( i = 1; i <= n; i++ )
        {
            scanf("%d%d",&node[i].A,&node[i].B);
            node[i].vis = false;
        }
        sort( &node[1],&node[1] + n,cmp);
        sum1 = 0;  b1 = m;
        sum2 = 0;  b2 = 0;
        ans  = 0,  count = n;

        for( i = 1; i <= n; i++ )
        if( node[i].A <= m && node[i].B > 0 )
        {
                sum1++;
                count--;
                node[i].vis = 1;
                b1 -= node[i].A;
                break;
         }

        for( i = 1; i <= n; i++ )
        if( node[i].B > 0 )
            ans += node[i].B;
        if( sum1 )
        {
            for( i = 1; i <= n; i++ )
            {
                if( count <= ans )
                {
                    ans = 0;
                    sum1 += count;
                    break;
                }
                if( !node[i].vis && b1 >= node[i].A )
                {
                    b1 -= node[i].A;
                    sum1++;
                    count--;
                }
            }
            sum1 += ans;
        }
        for( i = 1; i <= n; i++  )
        if( b2 >= node[i].A && node[i].B == 0 )
        {
            b2-= node[i].A;
            sum2++;
        }
        printf("Case %d: ",cas);
        if( sum1 > sum2 )
        {
            printf("%d %d\n",sum1,m-b1);
            continue;
        }
        if( sum2 > sum1 )
        {
            printf("%d %d\n",sum2,m-b2);
            continue;
        }
        if( b1 >= b2 )
              printf("%d %d\n",sum1,m-b1);
        else  printf("%d %d\n",sum1,m-b2);
    }

    system("pause");
    return 0;
}

/*
40

4 3
1 1
1 1
2 0
2 0

5 4
1 1
1 1
1 1
2 0
2 0

5 3
1 1
1 1
1 1
2 0
2 0

6 3
1 1
1 1
1 1
1 1
2 0
2 0

5 3
1 1
2 0
2 0
2 0
2 0

5 3
1 1
1 1
2 0
2 0
2 0

5 5
1 1
1 2
2 1
3 0
2 0

3 5
4 1
5 1
7 7

2 1
2 2
4 0

5 5
10 1
4 1
5 2
110 0
1 0

3 5
1 0
2 0
3 0

6 20
10 2
10 2
100 0
100 0
100 0
100 0

5 7
7 1
7 1
1 0
1 0
1 0

4 5
4 1
1 0
2 0
1 0

Case 1: 4 2
Case 2: 5 2
Case 3: 5 2
Case 4: 6 2
Case 5: 3 3
Case 6: 4 2
Case 7: 5 1
Case 8: 3 4
Case 9: 0 0
Case 10: 5 4
Case 11: 2 3
Case 12: 6 20
Case 13: 3 3
Case 14: 3 4

*/

 

posted on 2012-09-24 16:10  浪舟  阅读(126)  评论(0编辑  收藏  举报

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