Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.
The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.
1 class Solution { 2 public: 3 bool isValid(string s) { 4 stack<char> st; 5 int len = s.size(); 6 if (len % 2 != 0) 7 return false; 8 for (int i = 0; i < len; i++) 9 { 10 if (s[i] == '(' || s[i] == '[' || s[i] == '{') 11 st.push(s[i]); 12 else 13 { 14 if (st.size() == 0) 15 return false; 16 else 17 if (s[i] == m[st.top()]) 18 { 19 //cout << s[i] << m[st.top()] << endl; 20 st.pop(); 21 cout <<st.size()<<st.empty() << endl; 22 } 23 else 24 return false; 25 } 26 } 27 if (st.size() == 0) 28 return true; 29 else 30 return false; 31 } 32 map<char, char> m; 33 Solution() 34 { 35 m.insert(pair<char, char>('(', ')')); 36 m.insert(pair<char, char>('[', ']')); 37 m.insert(pair<char, char>('{', '}')); 38 } 39 };
