题目描述

给定一个数组和滑动窗口的大小,找出所有滑动窗口里数值的最大值。例如,如果输入数组{2,3,4,2,6,2,5,1}及滑动窗口的大小3,那么一共存在6个滑动窗口,他们的最大值分别为{4,4,6,6,6,5}; 针对数组{2,3,4,2,6,2,5,1}的滑动窗口有以下6个: {[2,3,4],2,6,2,5,1}, {2,[3,4,2],6,2,5,1}, {2,3,[4,2,6],2,5,1}, {2,3,4,[2,6,2],5,1}, {2,3,4,2,[6,2,5],1}, {2,3,4,2,6,[2,5,1]}。
 1 class Solution {
 2 public:
 3     vector<int> maxInWindows(const vector<int>& num, unsigned int size)
 4     {
 5             vector<int> vet;
 6             int len = num.size();
 7             if(len==0||size==0||size>len)
 8                 return vet;
 9             if(size==len)
10             {
11                   vector<int>  vet1 = num;
12                 sort(vet1.begin(), vet1.end());
13                 vet.push_back(vet1.back());
14                  return vet;
15                 }
16            
17         
18             int max =INT_MIN;
19             for (int i = 0; i <= len-size; i++)
20             {
21                 for (int j = i; j < i + size; j++)
22                 {
23                     if (max < num[j])
24                         max = num[j];
25 
26                 }
27                 vet.push_back(max);
28                 max = INT_MIN;
29             }
30             return vet;
31     }
32 };

 

posted on 2017-06-07 16:54  无惧风云  阅读(186)  评论(0编辑  收藏  举报