Json转行DataTable

     /// <summary>
/// {table:[{column1:1,column2:2,column3:3},{column1:1,column2:2,column3:3}]}
/// </summary>
/// <param name="strJson">Json字符串</param>
/// <returns></returns>
public static DataTable JsonToDataTable(string strJson)
{
//取出表名
Regex rg = new Regex(@"(?<={)[^:]+(?=:/[)", RegexOptions.IgnoreCase);
string strName = rg.Match(strJson).Value;
DataTable tb = null;
//去除表名
strJson = strJson.Substring(strJson.IndexOf("[") + 1);
strJson =strJson.Substring(0, strJson.IndexOf("]"));

//获取数据
rg = new Regex(@"(?<={)[^}]+(?=})");
MatchCollection mc = rg.Matches(strJson);
for (int i = 0; i < mc.Count; i++)
{
string strRow = mc[i].Value;
string[] strRows = strRow.Split(',');

//创建表
if (tb == null)
{
tb = new DataTable();
tb.TableName = strName;
foreach (string str in strRows)
{
DataColumn dc = new DataColumn();
string[] strCell = str.Split(':');
dc.ColumnName = strCell[0].ToString();
tb.Columns.Add(dc);
}
tb.AcceptChanges();
}

//增加内容
DataRow dr = tb.NewRow();
for (int r = 0; r < strRows.Length; r++)
{
dr[r] = strRows[r].Split(':')[1].Trim().Replace("", ",").Replace("", ":").Replace("/"", "");
}
tb.Rows.Add(dr);
tb.AcceptChanges();
}

return tb;
}
posted @ 2012-03-22 10:43  划破黑夜  阅读(550)  评论(0编辑  收藏  举报