LeetCode 190 Reverse Bits

解法1:

 1 class Solution{
 2 public:
 3     uint32_t reverseBits(uint32_t x){
 4         uint32_t res=0;
 5         for (int i=0;i<32;++i) {
 6             res |= ((x>>i)&1)<<(31-i);
 7         }
 8         return res;
 9     }
10 };

解法2:

class Solution{
public:
    uint32_t reverseBits(uint32_t x){
        uint32_t res=0;
        for (int i=0;i<32;++i) {
            if ((x&1)==1) {
                res = res<<1;
                res = res+1;
                x = x>>1;
            }
            else{
                res = res<<1;
                x = x>>1;
            }
        }
        return res;
    }
};

 

posted @ 2015-03-26 12:46  GodWU  阅读(137)  评论(0)  编辑  收藏  举报