处理Asp.net Ajax框架12029,12007错误

        <asp:ScriptManager ID="ScriptManager1" runat="server">
        
</asp:ScriptManager>

        
<script language="javascript" type="text/javascript">
    Sys.WebForms.PageRequestManager.getInstance().add_endRequest(EndRequestHandler); 
    
function EndRequestHandler(sender, args)
    
{
        
        
if (args.get_error() != undefined)
        
{
           
if ((args.get_response().get_statusCode() == '12007') || (args.get_response().get_statusCode() == '12029'))
           
{
                   
                   
                   document.writeln(
"服务器连接失败。");
                   window.onerror 
= false//JS中遇到脚本错误时不做任何操作

            }

        }

    }

        
</script>
posted @ 2007-11-15 15:33  吴碧宇  阅读(743)  评论(0编辑  收藏  举报