Python下载图片并保存本地的两种方式
一:使用Python中的urllib类中的urlretrieve()函数,直接从网上下载资源到本地,具体代码:
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import os,stat import urllib.request "d44&imgtype=jpg&er=1&src=http%3A%2F%2Fupload.qianhuaweb.com%2F2017%2F0718%2F1500369506683.jpg" file_path = 'D:/book/img' file_name = "pyt" try : #是否有这个路径 if not os.path.exists(file_path): #创建路径 os.makedirs(file_path) #获得图片后缀 file_suffix = os.path.splitext(img_url)[ 1 ] print (file_suffix) #拼接图片名(包含路径) filename = '{}{}{}{}' . format (file_path,os.sep,file_name,file_suffix) print (filename) #下载图片,并保存到文件夹中 urllib.request.urlretrieve(img_url,filename = filename) except IOError as e: print ( "IOError" ) except Exception as e: print ( "Exception" ) |
二:利用读写操作写入文件,具体代码:
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import os,stat import urllib.request for i in range ( 1 , 3 ): if not os.path.exists( "./rym" ): print ( "不纯在" ) os.makedirs( "./rym" ) else : print ( "存在" ) os.chmod( "D:/imagss" , 777 ) with urllib.request.urlopen( "https://timgsa.baidu.com/timg?image&quality=80&size=b9999_10000&sec=1516371301&di=d99af0828b" "b301fea27c2149a7070d44&imgtype=jpg&er=1&src=http%3A%2F%2Fupload.qianhuaweb.com%2F2017%2F0718%" "2F1500369506683.jpg" , timeout = 30 ) as response, open ( "./rym/lyj.png" , 'wb' ) as f_save: f_save.write(response.read()) f_save.flush() f_save.close() print ( "成功" ) |