INT_MIN绝对值
摘要:求某个int32的绝对值: unsigned int abs_n = n < 0 ? UINT_MAX - ((unsigned int)(n)) + 1U : (unsigned int)(n); Update: As @aka.nice suggests, we can actually rep
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posted @ 2021-12-20 21:17
posted @ 2021-12-20 21:17
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