Problem 2232 炉石传说

Problem 2232 炉石传说

不知道fzu的账号在哪里弄,想要做题的可以到vj上面去做 https://vjudge.net/problem/FZU-2232

#include <iostream>
#include <cstdio>
#include <vector>
#include <queue>
#include <cstring>
using namespace std;
const int maxn = 305, inf = 0x3f3f3f;
struct Edge {
    int from, to, cap, flow;
};
struct Dinic {
    int n, m, s, t;
    vector<Edge> edges;
    vector<int> G[maxn];
    bool vis[maxn];
    int d[maxn];
    int cur[maxn];

    void init(int n) {
        this->n = n;
        for (int i = 1; i <= n; ++i) {
            G[i].clear();
        }
        edges.clear();
    }
    void AddEdge(int from, int to, int cap) {
        edges.push_back((Edge){from, to, cap, 0});
        edges.push_back((Edge){to, from, 0, 0});
        m = edges.size();
        G[from].push_back(m-2);
        G[to].push_back(m-1);
    }
    bool bfs() {
        memset(vis, 0, sizeof(vis));
        queue<int> que;
        que.push(s);
        d[s] = 0;
        vis[s] = true;
        while (!que.empty()) {
            int x = que.front(); que.pop();
            for (int i = 0; i < G[x].size(); ++i) {
                Edge& e = edges[G[x][i]];
                if (!vis[e.to] && e.cap > e.flow) {
                    vis[e.to] = true;
                    d[e.to] = d[x] + 1;
                    que.push(e.to);
                }
            }
        }
        return vis[t];
    }
    int dfs(int x, int a) {
        if (x == t || a == 0) return a;
        int flow = 0, f;
        for (int& i = cur[x]; i < G[x].size(); ++i) {
            Edge& e = edges[G[x][i]];
            if (d[x] + 1 == d[e.to] && (f = dfs(e.to, min(a, e.cap-e.flow))) > 0) {
                e.flow += f;
                edges[G[x][i]^1].flow -= f;
                flow += f;
                a -= f;
                if (a == 0) break;
            }
        }
        return flow;
    }
    int maxflow(int s, int t) {
        this->s = s; this->t = t;
        int flow = 0;
        while (bfs()) {
            memset(cur,0,sizeof(cur));
            flow += dfs(s,inf);
        }
        return flow;
    }
}dinic;
int a[maxn], b[maxn], c[maxn], d[maxn];
int main() {
    int T; scanf("%d",&T);
    while (T--) {
        int n; scanf("%d",&n);
        int s = n+n+1, t = n+n+2;
        dinic.init(n*2+2);
        for (int i = 1; i <= n; ++i) {
            scanf("%d%d",&a[i],&b[i]);
            dinic.AddEdge(s,i,1);
        }
        for (int i = 1; i <= n; ++i) {
            scanf("%d%d",&c[i],&d[i]);
            dinic.AddEdge(i+n,t,1);
            for (int j = 1; j <= n; ++j) {
                if (b[j] >= c[i] && a[j] > d[i]) {
                    dinic.AddEdge(j,i+n,1);
                }
            }
        }

        int ans = dinic.maxflow(s,t);
        printf("%s\n",ans==n ? "Yes" : "No");
    }
    return 0;
}

 

posted @ 2019-11-02 22:03  麻辣猪仔  阅读(140)  评论(0编辑  收藏  举报