P1065 作业调度方案

一道傻逼模拟写了半个小时还wa了一次
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#include <cstdio>
#include <cstring>
#include <cassert>
#include <iostream>
#include <algorithm>
using namespace std;
const int MAXN = 20 + 5;
inline int read(){
	char ch = getchar(); int x = 0;
	while(!isdigit(ch)) ch = getchar();
	while(isdigit(ch)) x = x * 10 + ch - '0', ch = getchar();
	return x;
}

int N, M;
int a[MAXN * MAXN];
int idx[MAXN][MAXN], val[MAXN][MAXN];

int p[MAXN], ti[MAXN];
bool vis[MAXN][MAXN * MAXN];

inline bool ok(int &st, int &len, int &mac) {
	for(int i = st; i <= st + len - 1; i++) 
		if(vis[mac][i]) return false;
	for(int i = st; i <= st + len - 1; i++) vis[mac][i] = true;
	return true;
}

int main(){
	// freopen("p1065.in", "r", stdin);
	cin>>M>>N;
	for(int i = 1; i <= N * M; i++) a[i] = read();
	for(int i = 1; i <= N; i++)
		for(int j = 1; j <= M; j++) idx[i][j] = read();
	for(int i = 1; i <= N; i++)
		for(int j = 1; j <= M; j++) val[i][j] = read();

	for(int i = 1; i <= N * M; i++) {
		++p[a[i]]; int &t = ti[a[i]];
		while(!ok(t, val[ a[i] ][ p[a[i]] ], idx[ a[i] ][ p[a[i]] ])) ++t;
		t += val[ a[i] ][ p[a[i]] ];
	}

	int ans = 0;
	for(int i = 1; i <= N; i++) ans = max(ans, ti[i]); 
		
	printf("%d\n", ans);
	return 0;
}

posted @ 2018-10-13 10:10  俺是小程  阅读(305)  评论(0编辑  收藏  举报