洛谷P1119 灾后重建

利用Floyd最外层为中转点的性质。

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
const int MAXN = 200 + 10;
const int MAXQ = 5e4 + 20;
const int INF = 0x3f3f3f3f;
inline int read()
{
    int x = 0; char ch = getchar();
    while(!isdigit(ch)) ch = getchar();
    while(isdigit(ch)) x = x * 10 + ch -'0', ch = getchar();
    return x;
}

int N, M, Q;
int time[MAXN];
int dis[MAXN][MAXN];

inline void floyd(int x)
{
    for(int i = 0; i < N; i++)
        for(int j = 0; j < N; j++)
            if(dis[i][x] != INF && dis[x][j] != INF)
                dis[i][j] = min(dis[i][j], dis[i][x] + dis[x][j]);
}


int main()
{
    cin>>N>>M;
    memset(dis, 0x3f, sizeof(dis));
    for(int i = 0; i < N; i++) time[i] = read();
    for(int i = 0, u, v, c; i < M; i++){
        u = read(), v = read(), c = read();
        dis[u][v] = dis[v][u] = min(dis[u][v], c);
    }
    cin>>Q;
    int p = 0;
    while(Q--){
        int x = read(), y = read(), w = read();
        while(time[p] <= w && p < N) {
            floyd(p), ++p;
        }
        if(dis[x][y] == INF || time[x] > w || time[y] > w) puts("-1");
        else cout<<dis[x][y]<<endl;
    }
    return 0;
}

 

posted @ 2018-07-15 14:43  俺是小程  阅读(92)  评论(0编辑  收藏  举报