Umbraco 中获取一个media item的文件路径 file path

我们要使用UmbracoHelper, 这里就需要用到我们在之前的blog里面写的UmbracoContext

参看这个blog https://www.cnblogs.com/wphl-27/p/9927044.html

public class ContextHelpers
{

   public static UmbracoContext EnsureUmbracoContext()
   {

if(UmbracoContext != null)
         {
             return UmbracoContext.Current;
         }
      var dummyHttpContext = new HttpContextWrapper(new HttpContext(new SimpleWorkerRequest("blah.aspx", "", new StringWriter())));
            return UmbracoContext.EnsureContext(
                dummyHttpContext,
                ApplicationContext.Current,
                new WebSecurity(dummyHttpContext, ApplicationContext.Current),
                UmbracoConfig.For.UmbracoSettings(),
                UrlProviderResolver.Current.Providers,
                false);

    }
}

1. 在View 中

在View中写如下代码

UmbracoHelper uHelper = new UmbracoHelper(ContextHelper.EnsureUmbracoContext());

string mediaUrl = "";
if (CurrentPage.HasValue(propertyName))
{
    var mediaItem = uHelper.Media(CurrentPage.propertyName.ToString());
    mediaUrl = mediaItem.umbracoFile;
}
return mediaUrl;

2. 在后台代码中写

using Umbraco.Web;

public static string GetMediaUrlFromPropertyName(dynamic contentItem, string propertyName)
{
    UmbracoHelper uHelper = new UmbracoHelper(ContextHelper.EnsureUmbracoContext());
    string mediaUrl = "";
    if (contentItem.HasValue(propertyName))
    {
        var mediaItem = uHelper.Media(contentItem.GetPropertyValue(propertyName));
        mediaUrl = mediaItem.umbracoFile;
    }
    return mediaUrl;
}