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# 在有两个列表,
list1 = ['key1','key2','key3']
list2 = ['1','2','3']
#把他们转为这样的字典:
# {'key1':'1','key2':'2','key3':'3'}

list1 = ['key1','key2','key3']

list2 = ['1','2','3']

dict(zip(list1,list2))

# {'key1':'1','key2':'2','key3':'3'}

# 将嵌套列表转为字典,有两种方法,

new_list= [['key1','value1'],['key2','value2'],['key3','value3']]

dict(list)

# {'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}

# 或者这样:

new_list= [['key1','value1'],['key2','value2'],['key3','value3']]

new_dict = {}

 for i in new_list:

...   new_dict[i[0]] = i[1]                #字典赋值,左边为key,右边为value

...

 new_dict

#{'key3': 'value3', 'key2': 'value2', 'key1': 'value1'}
posted on 2018-10-21 11:37  conncent  阅读(1558)  评论(0编辑  收藏  举报