LeetCode | 0914. X of a Kind in a Deck of Cards卡牌分组【Python】
LeetCode 0914. X of a Kind in a Deck of Cards卡牌分组【Easy】【Python】【数学】
Problem
In a deck of cards, each card has an integer written on it.
Return true
if and only if you can choose X >= 2
such that it is possible to split the entire deck into 1 or more groups of cards, where:
- Each group has exactly
X
cards. - All the cards in each group have the same integer.
Example 1:
Input: deck = [1,2,3,4,4,3,2,1]
Output: true
Explanation: Possible partition [1,1],[2,2],[3,3],[4,4].
Example 2:
Input: deck = [1,1,1,2,2,2,3,3]
Output: false´
Explanation: No possible partition.
Example 3:
Input: deck = [1]
Output: false
Explanation: No possible partition.
Example 4:
Input: deck = [1,1]
Output: true
Explanation: Possible partition [1,1].
Example 5:
Input: deck = [1,1,2,2,2,2]
Output: true
Explanation: Possible partition [1,1],[2,2],[2,2].
Constraints:
1 <= deck.length <= 10^4
0 <= deck[i] < 10^4
问题
给定一副牌,每张牌上都写着一个整数。
此时,你需要选定一个数字 X,使我们可以将整副牌按下述规则分成 1 组或更多组:
- 每组都有 X 张牌。
- 组内所有的牌上都写着相同的整数。
仅当你可选的 X >= 2 时返回 true。
示例 1:
输入:[1,2,3,4,4,3,2,1]
输出:true
解释:可行的分组是 [1,1],[2,2],[3,3],[4,4]
示例 2:
输入:[1,1,1,2,2,2,3,3]
输出:false
解释:没有满足要求的分组。
示例 3:
输入:[1]
输出:false
解释:没有满足要求的分组。
示例 4:
输入:[1,1]
输出:true
解释:可行的分组是 [1,1]
示例 5:
输入:[1,1,2,2,2,2]
输出:true
解释:可行的分组是 [1,1],[2,2],[2,2]
提示:
1 <= deck.length <= 10^4
0 <= deck[i] < 10^4
思路
数学
直接调用 Python 的 collections 库,Counter 统计。
然后计算所有整数出现次数的最大公约数。
Python3代码
from typing import List
import collections
import math
class Solution:
def hasGroupsSizeX(self, deck: List[int]) -> bool:
# Counter统计出来是一个字典
c = list(collections.Counter(deck).values())
res = c[0]
# 求所有数的最大公约数
for x in c:
res = math.gcd(res, x)
return res > 1
GitHub链接
最怕一生碌碌无为,还说平凡难能可贵。