LeetCode | 0225. Implement Stack using Queues用队列实现栈【Python】

LeetCode 0225. Implement Stack using Queues用队列实现栈【Easy】【Python】【栈】【队列】

Problem

LeetCode

Implement the following operations of a stack using queues.

  • push(x) -- Push element x onto stack.
  • pop() -- Removes the element on top of the stack.
  • top() -- Get the top element.
  • empty() -- Return whether the stack is empty.

Example:

MyStack stack = new MyStack();

stack.push(1);
stack.push(2);  
stack.top();   // returns 2
stack.pop();   // returns 2
stack.empty(); // returns false

Notes:

  • You must use only standard operations of a queue -- which means only push to back, peek/pop from front, size, and is empty operations are valid.
  • Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
  • You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).

问题

力扣

使用队列实现栈的下列操作:

  • push(x) -- 元素 x 入栈
  • pop() -- 移除栈顶元素
  • top() -- 获取栈顶元素
  • empty() -- 返回栈是否为空

注意:

  • 你只能使用队列的基本操作-- 也就是 push to back, peek/pop from front, size, 和 is empty 这些操作是合法的。
  • 你所使用的语言也许不支持队列。 你可以使用 list 或者 deque(双端队列)来模拟一个队列 , 只要是标准的队列操作即可。
  • 你可以假设所有操作都是有效的(例如, 对一个空的栈不会调用 pop 或者 top 操作)。

思路

队列

数据结构基础
Python3代码
class MyStack:

    def __init__(self):
        """
        Initialize your data structure here.
        """
        self.myStack = []

    def push(self, x: int) -> None:
        """
        Push element x onto stack.
        """
        self.myStack.append(x)

    def pop(self) -> int:
        """
        Removes the element on top of the stack and returns that element.
        """
        # judge if it is empty
        if not self.empty():
            return self.myStack.pop()

    def top(self) -> int:
        """
        Get the top element.
        """
        # judge if it is empty
        if not self.empty():
            return self.myStack[-1]
        

    def empty(self) -> bool:
        """
        Returns whether the stack is empty.
        """
        return len(self.myStack) == 0
        


# Your MyStack object will be instantiated and called as such:
# obj = MyStack()
# obj.push(x)
# param_2 = obj.pop()
# param_3 = obj.top()
# param_4 = obj.empty()

代码地址

GitHub链接

posted @ 2020-03-01 22:56  Wonz  阅读(115)  评论(0编辑  收藏  举报