uva590 Always on the run(DP)

题目链接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=11&page=show_problem&problem=531

 

#include <iostream>
#include <cstdio>
#define ll long long
using namespace std;
int n,t;
ll dp[1010][12],a[12][12][33];
int c[12][12];
int main(){
    //freopen("590","r",stdin);
    int cas=1;
    while(cin>>n>>t){
        if(n==0&&t==0) break;
        for(int i=1;i<=n;i++){
           for(int j=1;j<=n;j++){
              if(i==j) continue;
              cin>>c[i][j];
              for(int k=0;k<c[i][j];k++){
                 cin>>a[i][j][k];
              }
           }
        }
        for(int i=0;i<1010;i++){
           for(int j=0;j<12;j++){
              dp[i][j]=(ll)1e16;
           }
        }
        dp[0][1]=0;
        for(int i=1;i<=t;i++){
           for(int j=1;j<=n;j++){
              for(int k=1;k<=n;k++){
                  //cout<<j<<" "<<k<<endl;
                  if(j==k||a[j][k][(i-1)%c[j][k]]==0) continue;
                  dp[i][k]=min(dp[i][k],dp[i-1][j]+a[j][k][(i-1)%c[j][k]]);
              }
           }
        }
        printf("Scenario #%d\n",cas++);
        if(dp[t][n]==(ll)1e16) printf("No flight possible.\n");
        else printf("The best flight costs %lld.\n",dp[t][n]);
        puts("");
    }
    return 0;
}
uva590

 

posted @ 2014-02-09 20:41  wonderzy  阅读(126)  评论(0编辑  收藏  举报