关于时间差的计算我总结了一下。
方法一:
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
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try
{
Date d1 = df.parse("2008-03-26 13:31:40");
Date d2 = df.parse("2008-01-02 11:30:24");
long diff = d1.getTime() - d2.getTime();
long days = diff / (1000 * 60 * 60 * 24);
}
catch (Exception e)
{
}
方法二:
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date now = df.parse("2008-03-26 13:31:40");
java.util.Date date=df.parse("2008-01-02 11:30:24");
long l=now.getTime()-date.getTime();
long day=l/(24*60*60*1000);
long hour=(l/(60*60*1000)-day*24);
long min=((l/(60*1000))-day*24*60-hour*60);
long s=(l/1000-day*24*60*60-hour*60*60-min*60);
System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");
方法三:
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date begin=dfs.parse("2008-01-02 11:30:24");
java.util.Date end = dfs.parse("2008-03-26 13:31:40");
long between=(end.getTime()-begin.getTime())/1000;//除以1000是为了转换成秒
![](https://www.cnblogs.com/Images/OutliningIndicators/None.gif)
long day1=between/(24*3600);
long hour1=between%(24*3600)/3600;
long minute1=between%3600/60;
long second1=between%60/60;
System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");
方法一:
![](https://www.cnblogs.com/Images/OutliningIndicators/None.gif)
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方法二:
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方法三:
![](https://www.cnblogs.com/Images/OutliningIndicators/None.gif)
![](https://www.cnblogs.com/Images/OutliningIndicators/None.gif)
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