摘要: 无源汇有上下界可行流 int main() { cin >> n >> m; S = 0; T = n + 1; for (int i = 1; i <= m; ++i) { x = read(); y = read(); L[i] = read(); r = read(); ADD(x, y, r 阅读全文
posted @ 2020-03-25 09:05 wljss 阅读(125) 评论(0) 推荐(0) 编辑