摘要: 斐波那契数列: f(0) = 0 f(1) = 1 f(2) = 1 f(3) = 2 f(4) = 3 f(5) = 8 .......f(n) = f(n - 2) + f(n - 1) 实现方法一: 阅读全文
posted @ 2017-06-10 17:04 wlgo2108 阅读(174) 评论(0) 推荐(0) 编辑