left join +group by;总结

SELECT v.name,COUNT(DISTINCT f.ID)AS family,COUNT(DISTINCT p.ID)AS person ,COUNT(DISTINCT pa.ID) AS man,COUNT(DISTINCT ps.ID)AS woman ,COUNT(DISTINCT c.id)AS car
FROM village AS v
LEFT JOIN family AS f ON f.villageID=v.ID AND f.building='3'
LEFT JOIN personnel AS p ON p.familyid=f.ID AND f.building='3'
LEFT JOIN personnel AS pa ON pa.familyid=f.ID AND pa.sex='男' AND f.building='3'
LEFT JOIN personnel AS ps ON ps.familyid=f.ID AND ps.sex='女' AND f.building='3'
LEFT JOIN car AS c ON c.familyid=f.ID AND f.building='3'
where  v.ID='d66cf963-2354-11e8-b8a0-f48e38f841f1'
GROUP BY f.building

已解决

 

 

https://www.cnblogs.com/kerrycode/p/5935704.html
这篇帖子对join的各种用法讲解比较清晰,可以参考一下

posted @   dreamw  阅读(650)  评论(0编辑  收藏  举报
编辑推荐:
· 记一次.NET内存居高不下排查解决与启示
· 探究高空视频全景AR技术的实现原理
· 理解Rust引用及其生命周期标识(上)
· 浏览器原生「磁吸」效果!Anchor Positioning 锚点定位神器解析
· 没有源码,如何修改代码逻辑?
阅读排行:
· 分享4款.NET开源、免费、实用的商城系统
· 全程不用写代码,我用AI程序员写了一个飞机大战
· MongoDB 8.0这个新功能碉堡了,比商业数据库还牛
· 白话解读 Dapr 1.15:你的「微服务管家」又秀新绝活了
· 上周热点回顾(2.24-3.2)
点击右上角即可分享
微信分享提示