Java中List集合去除重复数据的方法

1. 循环list中的所有元素然后删除重复

 1 public   static   List  removeDuplicate(List list)  {       
 2   for  ( int  i  =   0 ; i  <  list.size()  -   1 ; i ++ )  {       
 3       for  ( int  j  =  list.size()  -   1 ; j  >  i; j -- )  {       
 4            if  (list.get(j).equals(list.get(i)))  {       
 5               list.remove(j);       
 6             }        
 7         }        
 8       }        
 9     return list;       
10 }

2. 通过HashSet踢除重复元素

1 public static List removeDuplicate(List list) {   
2     HashSet h = new HashSet(list);   
3     list.clear();   
4     list.addAll(h);   
5     return list;   
6 }

3. 删除ArrayList中重复元素,保持顺序

 1 // 删除ArrayList中重复元素,保持顺序     
 2  public static void removeDuplicateWithOrder(List list) {    
 3     Set set = new HashSet();    
 4      List newList = new ArrayList();    
 5    for (Iterator iter = list.iterator(); iter.hasNext();) {    
 6          Object element = iter.next();    
 7          if (set.add(element))    
 8             newList.add(element);    
 9       }     
10      list.clear();    
11      list.addAll(newList);    
12     System.out.println( " remove duplicate " + list);    
13  }

4.把list里的对象遍历一遍,用list.contain(),如果不存在就放入到另外一个list集合中

1 public static List removeDuplicate(List list){  
2         List listTemp = new ArrayList();  
3         for(int i=0;i<list.size();i++){  
4             if(!listTemp.contains(list.get(i))){  
5                 listTemp.add(list.get(i));  
6             }  
7         }  
8         return listTemp;  
9     }

 

posted on 2019-03-22 11:35  江清澜静  阅读(240)  评论(0编辑  收藏  举报

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