huakaiyueluo

导航

公司框架常用函数和技巧

1.将json字符串转化为动态类型并调用

       dynamic d = JObject.Parse(actionModel.jsonEntity);

        string username = d.UserName.ToString();

 

2.将json字符串直接转换为对象

var actionModel = Utils.ParseFromJson<ActionModel>(action);
EmailInfo entity = (EmailInfo)Newtonsoft.Json.JsonConvert.DeserializeObject(actionModel.jsonEntity, typeof(EmailInfo));

posted on 2013-10-27 00:27  huakaiyueluo  阅读(363)  评论(0编辑  收藏  举报