写一个简单的bean
bean1.java
package bean; public class bean1 { String name="123123"; public String getName() { return name; } public void setName(String name) { this.name = name; } @Override public String toString() { return "bean1 [name=" + name + "]"; } }
bean2.java
package bean; public class bean2 { String name="0"; public void setBean1(bean1 bean1){ System.out.println(bean1); this.name=bean1.getName(); } @Override public String toString() { return "bean2 [name=" + name + "]"; } }
ApplicationContext.xml
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-4.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-4.0.xsd"> <bean name="bean1" class="bean.bean1"></bean> <bean name="bean2" class="bean.bean2"> <property name="bean1" ref="bean1"></property> </bean> </beans>
测试方法:
1 public void testBean(){ 2 ApplicationContext ac=new ClassPathXmlApplicationContext("applicationContext.xml"); 3 // System.out.println("ac:"+ac); 4 Object bean=ac.getBean("bean2"); 5 System.out.println("bean2:"+bean); 6 }