leetcode 57. Insert Interval
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).
You may assume that the intervals were initially sorted according to their start times.
Example 1:
Input: intervals = [[1,3],[6,9]], newInterval = [2,5]
Output: [[1,5],[6,9]]
Example 2:
Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]
Output: [[1,2],[3,10],[12,16]]
Explanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].
NOTE: input types have been changed on April 15, 2019. Please reset to default code definition to get new method signature.
- 从左到右处理分三步:
- 直接添加在目标区间左边的
- 合并和目标区间重合的
- 直接添加在目标区间右边的
- 时间复杂度
class Solution {
public:
vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) {
vector<vector<int>> res;
int n=intervals.size();
int i;
for(i=0;i<n;i++){
if(intervals[i][1]<newInterval[0])
res.push_back(intervals[i]);
else break;
}
vector<int> tmp=newInterval;
for(;i<n;i++){
if(intervals[i][1]>=newInterval[0])
tmp[0]=min(tmp[0],intervals[i][0]);
if(intervals[i][0]<=newInterval[1])
tmp[1]=max(tmp[1],intervals[i][1]);
if(intervals[i][0]>newInterval[1])
break;
}
res.push_back(tmp);
for(;i<n;i++)
res.push_back(intervals[i]);
return res;
}
};