C++ 在代码中获取字符串形式的类名

#include <iostream>
#include <string>
#include <typeinfo>
#include <cxxabi.h>

template <typename T>
class TypeTraits {
public:
    static std::string Name() {
        const char* name = typeid(T).name();
        std::string ret;
        int status = 0;
        char *demangled = abi::__cxa_demangle(name, 0, 0, &status);
        if (status == 0) {
            ret = std::string(demangled);
            std::free(demangled);
        } else {
            ret = std::string(name);
        }
        return ret;
    }
};

template <typename T>
class A {
};

int main() {
    static std::string name = TypeTraits<A<int>>::Name();
    std::cout << name << std::endl;  // output: A<int>
    return 0;
}

 

posted @ 2024-08-01 22:17  william-cheung  阅读(4)  评论(0编辑  收藏  举报