摘要: 处理四舍五入NSTimeIntervalInterval =305.721125;NSInteger timeInt = [[NSString stringWithFormat:@"%.0f", Interval] integerValue];Interval:305.721125timeInt:306 阅读全文
posted @ 2013-05-10 16:54 willbin 阅读(275) 评论(0) 推荐(0) 编辑