七.乱码问题

1.使用过滤器 （之前做web项目弄过，直接贴代码

package com.why;

import javax.servlet.*;
import java.io.IOException;

/**
 * @program: Spring_MVC
 * @description:
 * @author: @why
 * @create: 2020-08-19 15:40
 **/
public class EncodeFilter implements Filter {
    @Override
    public void init(FilterConfig filterConfig) throws ServletException {

    }

    @Override
    public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
        servletRequest.setCharacterEncoding("utf-8");
        filterChain.doFilter(servletRequest,servletResponse);
        servletResponse.setCharacterEncoding("utf-8");
    }
    @Override
    public void destroy() {

    }
}

 

web.xml的配置

<filter>
    <filter-name>encoding</filter-name>
    <filter-class>com.why.EncodeFilter</filter-class>
</filter>
    <filter-mapping>
        <filter-name>encoding</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

 

2.使用spring带的拦截器

<filter>
   <filter-name>encoding</filter-name>
   <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
   <init-param>
       <param-name>encoding</param-name>
       <param-value>utf-8</param-value>
   </init-param>
</filter>
<filter-mapping>
   <filter-name>encoding</filter-name>
   <url-pattern>/*</url-pattern>
</filter-mapping>

3.注意 /和/*

• < url-pattern>/</url-pattern>

• 会匹配到/login这样的路径型url，不会匹配到模式为*.jsp这样的后缀型url

• < url-pattern>/</url-pattern>

• 会匹配所有url：路径型的和后缀型的url(包括/login,.jsp,.js和*.html等)