04 2021 档案
摘要:网上能看到好多讲解四舍五入的 1. 其中第一个是用 round(x,n) x 表示要四舍五入的值,n表示保留几位小数 1 x = 2.225 n=2 ,输出 2.23 四舍五入 2 3 x= 2.215 n=2 ,输出 2.21 没有四舍五入 奇进偶舍的处理 可以改成这种方式 round(x*100
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摘要:地址: https://www.nowcoder.com/practice/dd0c6b26c9e541f5b935047ff4156309?tpId=37&tqId=21324&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:itertools 模块的官方解释: Functional tools for creating and using iterators. (用于创建和使用迭代器的函数工具) 1. product(*iterables, repeat=1) 用于求多个可迭代对象的笛卡尔积(Cartesian Pro
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摘要:上一文中实现eval方法如下 ScriptEngineManager manager = new ScriptEngineManager(); ScriptEngine se = manager.getEngineByName("js");本文实现该方法,将字符串转成运算符(菜鸟一个,大佬们多多指点
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摘要:1 import javax.script.ScriptEngine; 2 import javax.script.ScriptEngineManager; 3 import javax.script.ScriptException; 4 5 /** 6 * 有1个字符串(包含若干个加减乘除运算列)
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摘要:python: 1 import random 2 3 def randomMore(min,max,n): 4 res = [] 5 while len(res) != n: 6 num = random.randrange(min,max) 7 if num not in res: 8 res.
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摘要:题目: https://www.nowcoder.com/practice/8f3df50d2b9043208c5eed283d1d4da6?tpId=37&tqId=21228&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:1 # @Author :whyCai 2 # @Time :2021/4/8 23:28 3 4 ''' 5 6 输入一串数字,以空格相隔,要走到最短路径,输出最短路径的步数,如果没有,输出-1 7 要求: 8 1.第一步 大于1小于长度的一半 9 2.以后的步数为第一步走到该数字的步数 10 1
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摘要:参考地址(亲测有效): https://blog.csdn.net/qq_38060935/article/details/90377761
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摘要:地址: https://www.nowcoder.com/practice/64f6f222499c4c94b338e588592b6a62?tpId=37&tqId=21328&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:题目链接: https://www.nowcoder.com/practice/3245215fffb84b7b81285493eae92ff0?tpId=37&tqId=21226&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranki
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摘要:地址: https://www.nowcoder.com/practice/6abde6ffcc354ea1a8333836bd6876b8?tpId=37&tqId=21320&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:题目: https://www.nowcoder.com/practice/d9162298cb5a437aad722fccccaae8a7?tpId=37&tqId=21227&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:地址: https://www.nowcoder.com/practice/119bcca3befb405fbe58abe9c532eb29?tpId=37&tqId=21240&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:题目: https://www.nowcoder.com/practice/196534628ca6490ebce2e336b47b3607?tpId=37&tqId=21229&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:1 def calcStr(s): 2 ''' 3 4 有1个字符串(包含若干个加减乘除运算列),格式如下:2*3/7-1*6+4=;1.5+1/4*3.243-5*6=;2.32+30/4-64*1=;......" * ,请编写代码计算结果(保留2位小数) 5 预期输出: 6 2*3/7-1*6
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摘要:地址: https://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1?tpId=37&tqId=21232&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:地址: https://www.nowcoder.com/practice/48b3cb4e3c694d9da5526e6255bb73c3?tpId=37&tqId=21236&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:地址: https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe?tpId=37&tqId=21234&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:地址: https://www.nowcoder.com/practice/eb94f6a5b2ba49c6ac72d40b5ce95f50?tpId=37&tqId=21233&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:题目链接: https://www.nowcoder.com/practice/a35ce98431874e3a820dbe4b2d0508b1?tpId=37&tqId=21225&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranki
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摘要:地址: https://www.nowcoder.com/practice/440f16e490a0404786865e99c6ad91c9?tpId=37&tqId=21238&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:地址: https://www.nowcoder.com/practice/de044e89123f4a7482bd2b214a685201?tpId=37&tqId=21231&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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摘要:题目: https://www.nowcoder.com/practice/3ab09737afb645cc82c35d56a5ce802a?tpId=37&tqId=21230&rp=1&ru=%2Fta%2Fhuawei&qru=%2Fta%2Fhuawei%2Fquestion-ranking
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