leetcode 7. Reverse Integer [java]

    public int reverse(int x) {
        long res = 0;
        while (x != 0){
            res = res* 10 + x % 10;
            x /= 10;
        }
        if(res >= Integer.MAX_VALUE || res < Integer.MIN_VALUE)
            return 0;
        return (int)res;
    }