牛客网-剑指Offer-复杂链表的复制

题目链接：https://www.nowcoder.com/practice/f836b2c43afc4b35ad6adc41ec941dba?tpId=13&tqId=11178&rp=2&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking

 

看了半天没看懂什么意思，原来就是复制一个链表，但是地址不能和原来相同。

主要涉及指针的理解。

class Solution {
public:
    RandomListNode* Clone(RandomListNode* pHead)
    {
        if(pHead == NULL)
            return NULL;

        map<RandomListNode* , RandomListNode* > mp;
        RandomListNode* cur = pHead;
        RandomListNode* res = pHead;

        while(cur)
        {
            mp[cur] = new RandomListNode(cur->label);
            cur = cur->next;
        }

        while(pHead)
        {
            cur = mp[pHead];
            cur->random = mp[pHead->random];

            if(pHead->next)
                cur->next = mp[pHead->next];

            pHead = pHead->next;
            cur = cur->next;
        }

        return mp[res];
    }
};