【组队训练】2014鞍山区域赛
三题,排名98,铜尾……
说实话,这样下去真的很害怕,感觉每次都是铜尾阿= = 等正式比赛时一点失误不就tm又铁了嘛。。。。
刚开始很多人过I题,zr看了下直接写的。1A
然后部分人过了E,我看了下,水dp,随便敲了下,1A
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const int N = 105; int a[N]; int s[N][N]; int dp[N][N]; int main() { //freopen("in.txt", "r", stdin); int T; scanf("%d", &T); while (T--) { int n, m; scanf("%d%d", &n, &m); for (int i = 1; i <= m; ++i) { for (int j = 1; j <= m; ++j) { scanf("%d", &s[i][j]); } } for (int i = 1; i <= n; ++i) { scanf("%d", a+i); } memset(dp, -1, sizeof dp); if (a[1] != -1) dp[1][a[1]] = 0; else { for (int j = 1; j <= m; ++j) { dp[1][j] = 0; } } for (int i = 2; i <= n; ++i) { if (a[i] != -1) { for (int k = 1; k <= m; ++k) { if (dp[i-1][k] < 0) continue; dp[i][a[i]] = max(dp[i][a[i]], dp[i-1][k] + s[k][a[i]]); } continue; } for (int j = 1; j <= m; ++j) { for (int k = 1; k <= m; ++k) { if (dp[i-1][k] < 0) continue; dp[i][j] = max(dp[i][j], dp[i-1][k] + s[k][j]); } } } int ans = 0; for (int j = 1; j <= m; ++j) { ans = max(ans, dp[n][j]); } printf("%d\n", ans); } return 0; }
然后就很坎坷了- -
D题我们讨论得出重心是每个点的和除以点的个数,和只需要找n-k个数就可以了,剩下的放在重心就好了。
zr贪心写了一发,没过。
我看好了B题(大模拟),想写一下,zr说他写,让我想其他题。
于是我想了下D,觉得选择的区域应该是连续的,遍历一便就可以了。这时zrB题wa了。我写D,也wa……
很尴尬的时刻QAQ
查了半个小时,查出来少了回车(妈蛋啊啊啊)3A
#include <cstdio> #include <cstring> #include <vector> #include <algorithm> #include <iostream> #include <map> #include <queue> #include <stack> #include <cmath> //#pragma comment(linker, "/STACK:102400000,102400000") using namespace std; #define PF(x) cout << "debug: " << x << " "; #define EL cout << endl; #define PC(x) puts(x); typedef long long ll; #define CLR(x, v) sizeof (x, v, sizeof(x)) using namespace std; const int INF = 0x5f5f5f5f; const int N= 2e5 + 10; const int mod=1e9 + 7; const int maxn = 5e4 + 10; double a[maxn]; double sum[maxn]; int main() { //freopen("in.txt","r",stdin); int T; scanf("%d", &T); while (T--) { int n ,k; scanf("%d%d", &n, &k); for (int i = 1; i <= n; ++i) { scanf("%lf", a+i); } if (n <= k+1) { printf("0\n"); continue; } sort(a+1, a+1+n); for (int i = 1; i <= n; ++i) { // qianzhuihe sum[i] = sum[i-1] + a[i]; } int x = n-k; double tot = 0, tmp = 0; for (int i = 1; i <= x; ++i) { tot += a[i]; tmp += a[i]*a[i]; } double cer; cer = tot / x; // zhongxin tmp = tmp + cer * cer * x - 2 * cer * sum[x]; double ans = tmp; for (int i = x+1; i <= n; ++i) { tmp = tmp + 2*cer*(sum[i-1]-sum[i-1-x]) - cer*cer*x - a[i-x]*a[i-x]; tot = tot + a[i] - a[i-x]; cer = tot / x; tmp = tmp + a[i]*a[i] - 2*cer*(sum[i]-sum[i-x]) + cer*cer*x; ans = min(ans, tmp); } printf("%.10f\n", ans); } return 0; }
B题题意不明确,试了好多种题意,还是没过。(赛后发现代码也确实有一些问题- -
一道数论相对简单的题没过,学弟果然还是弱一些= =
sigh……