Pyhthon计算文件夹大小

 

 

不使用递归
import os
from os.path import join, getsize
def getdirsize(dir):
    size = 0
    for root, dirs, files in os.walk(dir):
        size += sum([getsize(join(root, name)) for name in files])
    return size
size = getdirsize(r'D:\python_code')
print('There are %.3f' % (size / 1024 / 1024), 'Mbytes in D:\\python_code')