python 递归遍历目录筛选特定文件名的文件

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#!/usr/bin/python   import os import sys     list=[] folder_path="/root" def search_files(folder_path):       search_string = "测试"       for root, dirs, files in os.walk(folder_path):           for name in files:               if search_string  in name:                   f = os.path.join(root, name)                 list.append(f)     print(list)   search_files(folder_path)

　　

python 234.py
['/root/测试123.xlsx', '/root/123/测试99ee.xlsx', '/root/123/345/测试999.txt']