shell获取某个时间段的nginx日志内容

shell获取某个时间段的nginx日志内容

小醉90s 2014-04-06 16:40:36 15297 收藏 1
分类专栏： linux
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从nginx日志中获取2014:04:01日 21:30至21:50的日志内容

# cat web.log

192.168.16.105 - - [01/Apr/2014:21:26:21 +0800] "GET / HTTP/1.1" 502 172
192.168.16.105 - - [01/Apr/2014:21:28:22 +0800] "GET / HTTP/1.1" 502 172 
192.168.16.105 - - [01/Apr/2014:21:31:36 +0800] "GET / HTTP/1.1" 502 172 
192.168.16.105 - - [01/Apr/2014:21:42:14 +0800] "GET / HTTP/1.1" 502 172  
192.168.16.105 - - [01/Apr/2014:21:45:22 +0800] "GET / HTTP/1.1" 502 172 
192.168.16.105 - - [01/Apr/2014:21:46:32 +0800] "GET / HTTP/1.1" 502 172 
192.168.16.105 - - [01/Apr/2014:21:46:54 +0800] "GET / HTTP/1.1" 502 172 
192.168.16.105 - - [01/Apr/2014:21:47:03 +0800] "GET / HTTP/1.1" 502 172  
192.168.16.105 - - [01/Apr/2014:21:48:31 +0800] "GET / HTTP/1.1" 200 26 
192.168.16.105 - - [01/Apr/2014:21:50:08 +0800] "GET / HTTP/1.1" 200 26  
192.168.16.105 - - [01/Apr/2014:21:51:21 +0800] "GET / HTTP/1.1" 200 26    
192.168.16.105 - - [01/Apr/2014:21:52:48 +0800] "GET / HTTP/1.1" 200 26 
方法1：sed


cat web.log | egrep "01/Apr/2014" | sed -n '/21:31:36/,/21:50:08/p'
方法二：awk


cat web.log | egrep "01/Apr/2014" | awk -F':' '$2 = 21 && $3 >= 30 && $3 <= 50'
注意：

1、sed中取的两个时间点21:31:36与21:50:08必须是日志中实际存在的，用21:30:01与21:50:01获取不到数据；
2、awk中$3小于等于50，包含了50:01-50:59的日志数据；

posted @ 2021-11-15 09:59  Oops!#  阅读(394)  评论(0)  编辑  收藏  举报