C# post json和接收json

HttpHelper

using MyCLib;
using System;
using System.Data;
using System.Data.OleDb;
using System.Globalization;
using System.IO;
using System.Text;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using FileEncoding;
using System.Text.RegularExpressions;
using Newtonsoft.Json.Linq;
using Newtonsoft.Json;
using System.Collections.Generic;
using System.Net;

public class HttpHelper
{
    public static JObject PostJson(string url, Dictionary<string, object> param)
    {
        string paramStr = JsonConvert.SerializeObject(param);
        byte[] data = System.Text.Encoding.UTF8.GetBytes(paramStr);
        var request = (HttpWebRequest)WebRequest.Create(url);
        request.Method = "POST";
        request.ContentType = "application/json";

        Stream newStream = request.GetRequestStream();
        newStream.Write(data, 0, data.Length);
        newStream.Close();

        request.ServicePoint.Expect100Continue = false;
        request.ProtocolVersion = HttpVersion.Version11;

        var response = (HttpWebResponse)request.GetResponse();
        var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();
        if (response.StatusCode == System.Net.HttpStatusCode.OK)
        {
            return JObject.Parse(responseString);
        }

        return null;
    }
    public static JObject GetJson(string url)
    {
        var request = (HttpWebRequest)WebRequest.Create(url);
        var response = (HttpWebResponse)request.GetResponse();
        var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();
        if (response.StatusCode == System.Net.HttpStatusCode.OK)
        {
            return JObject.Parse(responseString);
        }
        return null;
    }
}

 

p1:post json

Dictionary<string, object> dict = new Dictionary<string, object>();
        dict.Add("id", 1);
        dict.Add("name", "张三");
        dict.Add("age", 100);

        string url = MyCLib.StrClass.GetDomain() + "http://www.ceshi.com/p2.aspx";
        string json = HttpHelper.PostJson(url, dict).ToString();

        Response.Write(json);

 

p2:接收 json

var sr = new StreamReader(System.Web.HttpContext.Current.Request.InputStream);
            var stream = sr.ReadToEnd();
            var dict = JsonConvert.DeserializeObject<Dictionary<object, object>>(stream);
            dict.Add("time", DateTime.Now.ToString());

            string json = JsonConvert.SerializeObject(dict);

            Response.Write(json);
            Response.End();

 

posted @ 2021-03-18 09:40  WebApi  阅读(8468)  评论(0编辑  收藏  举报
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