矩阵中的路径 剑指offer65题

include "stdafx.h"

#include<vector>
#include<algorithm>
#include<string>
#include<iostream>
#include<stack>
using namespace std;

class Solution {
public:
	
	bool hasPath(char* matrix, int rows, int cols, char* str)
	{
		vector<vector<bool>> visited(rows, vector<bool>(cols,false));
		vector<vector<char>> mat(rows, vector<char>(cols, 'a'));
		vector<char> s;
		for (int i = 0;i < rows;i++)
		{
			for (int j = 0;j < cols;j++)
			{
				mat[i][j] =matrix[ i*cols + j];
			}
		}
		for (int i = 0;i < strlen(str);i++)
		{
			s.push_back(str[i]);
		}
		bool flag = false;
		for (int i = 0;i < rows;i++)
		{
			
			for (int j = 0;j < cols;j++)
			{
				if (mat[i][j] == str[0])
				{
					if (getPath(mat, i, j, s, 0, visited) == true)
					{
						flag = true;
						break;
					}
				}
				if (flag == true)
				{
					break;
				}
			}
		}
		return flag;
	}
	bool getPath(vector<vector<char>> mat, int rows, int cols, vector<char> s,int num, vector<vector<bool>> visited)
	{
		if (num == s.size() - 1 && mat[rows][cols] == s[num])
			return true;
		if (mat[rows][cols] == s[num])
		{
			visited[rows][cols] = true; //已经被访问
			num++;
			bool left = false;
			bool right = false;
			bool up = false;
			bool down = false;
			//向左走
			if (cols - 1 >= 0 && visited[rows][cols - 1] == false)
				left = getPath(mat, rows, cols - 1, s, num, visited);
			//向右走
			if (cols + 1 < mat[0].size() && visited[rows][cols + 1] == false)
				right = getPath(mat, rows, cols + 1, s, num, visited);
			//向上走
			if (rows - 1 >= 0 && visited[rows - 1][cols] == false)
				up = getPath(mat, rows - 1, cols, s, num, visited);
			//向下走
			if (rows + 1 < mat.size() && visited[rows + 1][cols] == false)
				down = getPath(mat, rows + 1, cols, s, num, visited);
			visited[rows][cols] = false;
			return left || right || up || down;
		}
		else
		{
			return false;
		}
		
	}

};
int main()
{
	Solution s;
	cout << s.hasPath("ABCESFCSADEE", 3, 4, "ABCCED") << endl;

	return 0;
}