果园里有一堆苹果,一共n头(n大于1小于9)熊来分,第一头为小东,它把苹果均分n份后,多出了一个,它扔掉了这一个,拿走了自己的一份苹果,接着第二头熊重复这一过程,即先均分n份,扔掉一个然后拿走一份,以此类推直到最后一头熊都是这样(最后一头熊扔掉后可以拿走0个,也算是n份均分)。问最初这堆苹果最少有多少个。

include "stdafx.h"

// ConsoleApplication12.cpp : 定义控制台应用程序的入口点。
//

#include<iostream>
#include<vector>
using namespace std;

class Apples {
public:
	int num = 0;
	int getInitial(int n) {
		// write code here
		int remianApple = 1;
		int appleNums = n;
		
	//	while(true)
			while (true)
		{
			bool flag = false;
			remianApple = appleNums;
			int num = n;
		//	cout << "#########  " << appleNums << "  ##################" << endl;
			while (num!=0) //
			{
				if (remianApple<= 0)
				{
					break;
				}
				else if ( remianApple%n != 1) //不符合要求,每次都不剩下1个苹果
				{
					break;
				}
				else {
					//循环完毕,找到对应的苹果数目
					int getApple = (remianApple - 1) / n;//每次拿走的苹果数目
					remianApple = remianApple - getApple-1;
				//  cout << num << ": " << " getApple:" << getApple << " remianApple:" << remianApple << endl;;
			//		cout << "num:" << num << endl;
					num = num - 1;
				}
			}
			if (num == 0)
			{
			//	cout << "remianApple:" << remianApple << endl;
				break;
			}
			appleNums++;
		}
		return  appleNums;
	}
	
};
int main()
{
	Apples apple;
	int i;
	while (cin>>i)
	{
	//	cout << "共有的苹果:" ;
		cout << apple.getInitial(i) << endl;
	}
	
	return 0;
}
posted @ 2017-02-23 14:54  wdan2016  阅读(1216)  评论(1编辑  收藏  举报