求出1~13的整数中1出现的次数,并算出100~1300的整数中1出现的次数?为此他特别数了一下1~13中包含1的数字有1、10、11、12、13因此共出现6次,但是对于后面问题他就没辙了。ACMer希望你们帮帮他,并把问题更加普遍化,可以很快的求出任意非负整数区间中1出现的次数。

// test20.cpp : 定义控制台应用程序的入口点。
//

include "stdafx.h"

include

include

include

include

include

include

include<string.h>

include

using namespace std;

class Solution {
public:
int NumberOf1Between1AndN_Solution(int n)
{
// int num=1;
int count = 0;
for (int i = 0;i <= n;i++)
{
int num = i;
do {
if (num % 10 == 1)
{
++count;
}
num = num / 10;
} while (num!=0);
}

	return count;
}

};
int main()
{

Solution so;
//int count=so.NumberOf1Between1AndN_Solution(13);
cout <<"count:" << so.NumberOf1Between1AndN_Solution(1)<< endl;



cout << endl;
return 0;

}

posted @ 2016-11-01 21:14  wdan2016  阅读(236)  评论(0编辑  收藏  举报