【GET请求转POST】JS Form提交实现页面跳转
1 //path:请求地址;key、value:参数键值 2 var postForm = document.createElement("form"); 3 postForm.method = "post"; 4 postForm.action = path; 5 postForm.style = "display:none"; 6 7 var parameterInput = document.createElement("input"); 8 parameterInput.setAttribute("name", key); 9 parameterInput.setAttribute("value",value); 10 11 postForm.appendChild(parameterInput); 12 13 document.body.appendChild(postForm); 14 15 postForm.submit();