树的一些操作——遍历,前序和中序建立后续

  1 #include <iostream>
  2 #include <cstring>
  3 #include <stack>
  4 #include <queue>
  5 #include <cmath>
  6 #include <exception>
  7 #include <stdexcept>
  8 
  9 using namespace std;
 10 
 11 typedef struct Node {
 12     int key;
 13     struct Node *left;
 14     struct Node *right;
 15 }Node;
 16 
 17 
 18 void PreOrder(Node* head) {
 19     if(head) {
 20         cout<<head->key<<"\t";
 21         PreOrder(head->left);
 22         PreOrder(head->right);
 23     }
 24 }
 25 
 26 void InOrder(Node* head) {
 27     if(head) {
 28         InOrder(head->left);
 29         cout<<head->key<<"\t";
 30         InOrder(head->right);
 31     }
 32 }
 33 
 34 void PostOrder(Node* head) {
 35     if(head) {
 36         PostOrder(head->left);
 37         PostOrder(head->right);
 38         cout<<head->key<<"\t";
 39     }
 40 }
 41 
 42 void IterInOrder(Node* head) {
 43     stack<Node*> ss;
 44     Node* headCp = head;
 45     for(;;) {
 46         for(;headCp;headCp=headCp->left) {
 47             ss.push(headCp);
 48         }
 49         if(ss.size()!=0) { // key point, if stack is of no item inside, top() will cause trouble.
 50             headCp = ss.top();
 51             ss.pop();
 52         }
 53         if(!headCp) {
 54             break;
 55         }
 56         cout<<headCp->key<<"\t";
 57         headCp = headCp->right;
 58     }
 59 }
 60 
 61 void LevelOrder(Node* head) {
 62     queue<Node*> que;
 63     if(!head) {
 64         return;
 65     }
 66     que.push(head);
 67     for(;;) {
 68         if(que.size()==0) {
 69             break;
 70         }
 71         head = que.front();
 72         que.pop();
 73         if(head) {
 74             cout<<head->key<<"\t";
 75             if(head->left) {
 76                 que.push(head->left);
 77             }
 78             if(head->right) {
 79                 que.push(head->right);
 80             }
 81         }
 82     }
 83 }
 84 
 85 Node* BuildTree(int* startPreorder, int* endPreorder, int* startInorder, int* endInorder);
 86 
 87 Node* ConstructNewTree(int* PreOrderArr, int* InOrderArr, int length) {
 88         if(PreOrderArr == NULL || InOrderArr == NULL || length == 0) {
 89             return NULL;
 90         } else {
 91             int* startPreorder = PreOrderArr;
 92             int* endPreorder = PreOrderArr+length-1;
 93             int* startInorder = InOrderArr;
 94             int* endInorder = InOrderArr+length-1;
 95             return BuildTree(startPreorder,endPreorder,startInorder,endInorder);
 96         }
 97 }
 98 
 99 Node* BuildTree(int* startPreorder, int* endPreorder, int* startInorder, int* endInorder) {
100     int rootValue = -1;
101     if(startPreorder == NULL || endPreorder==NULL || startInorder==NULL || endInorder==NULL) {
102         return NULL;
103     } else {
104         rootValue = *startPreorder;
105     }
106     Node* root = new Node();
107     root->key = rootValue;
108     root->left = NULL;
109     root->right = NULL;
110 
111     if(startPreorder==endPreorder) {
112         if(startInorder==endInorder && *startPreorder == *startInorder) {
113             return root;
114         } else {
115             throw exception();
116         }
117     }
118 
119     int* rootInorder = startInorder;
120     while(rootInorder<=endInorder && *rootInorder!=rootValue) {
121         rootInorder++;
122     }
123     if(*rootInorder!=rootValue) {
124         throw exception();
125     }
126     int leftLen = rootInorder-startInorder;
127     int righLen = endInorder-rootInorder;
128     int* leftPreorderEnd = startPreorder+leftLen;
129     if(leftLen>0) {
130         root->left = BuildTree(startPreorder+1,leftPreorderEnd,startInorder,rootInorder-1);
131     }
132     if(righLen>0) {
133         root->right = BuildTree(leftPreorderEnd+1,endPreorder,rootInorder+1,endInorder);
134     }
135     return root;
136 }
137 
138 
139 int main(int argc, char* argv[]) {
140     Node node1,node2,node3,node4,node5,node6,node7,node8;
141 
142     node1.key = 1;
143     node1.left = &node2;
144     node1.right = &node3;
145 
146     node2.key = 2;
147     node2.left = &node4;
148     node2.right = NULL;
149 
150     node3.key = 3;
151     node3.left = &node5;
152     node3.right = &node6;
153 
154     node4.key = 4;
155     node4.left = NULL;
156     node4.right = &node7;
157 
158     node5.key = 5;
159     node5.left = NULL;
160     node5.right = NULL;
161 
162     node6.key = 6;
163     node6.left = &node8;
164     node6.right = NULL;
165 
166     node7.key = 7;
167     node7.left = NULL;
168     node7.right = NULL;
169 
170     node8.key = 8;
171     node8.left = NULL;
172     node8.right = NULL;
173 
174     cout<<"preorder:"<<endl;
175     PreOrder(&node1);
176     cout<<endl;
177 
178     cout<<"inorder:"<<endl;
179     InOrder(&node1);
180     cout<<endl;
181 
182 
183 /*
184     cout<<"PreOrder:\n";
185     PreOrder(&node1);
186     cout<<endl;
187 
188     cout<<"recursive InOrder:\n";
189     InOrder(&node1);
190     cout<<endl;
191 
192     cout<<"loop InOrder:\n";
193     IterInOrder(&node1);
194     cout<<endl;
195 
196     cout<<"PostOrder:\n";
197     PostOrder(&node1);
198     cout<<endl;
199 
200     cout<<"Level Order:\n";
201     LevelOrder(&node1);
202     cout<<endl;
203 */
204 
205     cout<<"start building the tree ..."<<endl;
206     int PreorderArr[] = {1,2,4,7,3,5,6,8};
207     int InorderArr[] = {4,7,2,1,5,3,8,6};
208     Node* root = ConstructNewTree(PreorderArr,InorderArr,sizeof(PreorderArr)/sizeof(int));
209     cout<<"build done."<<endl;
210 
211     cout<<"preorder:"<<endl;
212     PreOrder(root);
213     cout<<endl;
214     cout<<"inorder:"<<endl;
215     InOrder(root);
216     cout<<endl;
217     cout<<"postorder:"<<endl;
218     PostOrder(root);
219     cout<<endl;
220 
221     return 0;
222 }

 

posted @ 2014-09-22 11:44  warnet  阅读(283)  评论(0编辑  收藏  举报