存个代码

#include <iostream>
#include <cstdio>
#include <queue>
#include <algorithm>
#include <cmath>
#include <cstring>
#define inf 2147483647
#define N 1000010
#define p(a) putchar(a)
#define For(i,a,b) for(int i=a;i<=b;++i)
//by war
//2019.8.16
using namespace std;
int T,n;
double L,r,mid,W,L,D,V,w[N],r[N],eps=1e-10,ans,pai=3.141592653589793;
void in(int &x){
    int y=1;char c=getchar();x=0;
    while(c<'0'||c>'9'){if(c=='-')y=-1;c=getchar();}
    while(c<='9'&&c>='0'){ x=(x<<1)+(x<<3)+c-'0';c=getchar();}
    x*=y;
}
void o(int x){
    if(x<0){p('-');x=-x;}
    if(x>9)o(x/10);
    p(x%10+'0');
}

double v(double r){
    return 4.0000000/3.00000000*pai*pow(r,3);
}

double deal(double h,int i){
    return pai*(r[i]*r[i]*h-h*h*h/3.0);
}

double lj(double x,int i){
    if(x-r[i]>eps)
        return v(r[i])/2.0+deal(min(2.0*r[i],x-r[i]),i);
    return v(r[i])/2.0-deal(r[i]-x);
}

bool check(double x){
    double t=V;
    For(i,1,n){
        if(1.0000000-w[i]>eps){
            t+=min(v(r[i])*w[i],lj(x,i));
        }
        else
            t+=lj(x,i);
    }
    if(t/W/L-x>eps)
        return 0;
    return 1;
}
signed main(){
    in(T);
    while(T--){
        in(n);
        cin>>W>>L>>D>>V;
        if(V<eps){
            puts("0.0000000000");
            continue;
        }
        For(i,1,n)
            cin>>r[i]>>w[i];
        
        l=0;r=D;
        while(r-l>eps){
            mid=(l+r)/2.0;
            if(check(mid))
                l=mid;
            else
                r=mid;
        }

    }
    return 0;
}

上面是排位赛6 

下面是排位赛7

 

#include <iostream>
#include <cstdio>
#include <queue>
#include <algorithm>
#include <cmath>
#include <cstring>
#define inf 2147483647
#define N 1000010
#define p(a) putchar(a)
#define For(i,a,b) for(int i=a;i<=b;++i)
//by war
//2019.8.18
using namespace std;
int T,n,m,cnt,l,L,R,num;
double k,t,ans,temp;
double b[N],PI=3.14159265357939788292;
bool vis[20][20][200000],flag;//zuo you xiajie shangjie

struct Node{
    double r,t;
}a[N];

void in(int &x){
    int y=1;char c=getchar();x=0;
    while(c<'0'||c>'9'){if(c=='-')y=-1;c=getchar();}
    while(c<='9'&&c>='0'){ x=(x<<1)+(x<<3)+c-'0';c=getchar();}
    x*=y;
}
void o(int x){
    if(x<0){p('-');x=-x;}
    if(x>9)o(x/10);
    p(x%10+'0');
}

double S(double x1,double x2){//类扇形的面积
    return 1.0/6.0*k*k*(x2*x2*x2-x1*x1*x1);
}

void clear(){
    memset(vis,0,sizeof(vis));
    flag=0;
    ans=0;
}

signed main(){
    in(T);
    while(T--){
        clear();
        cin>>k;
        in(n);
        For(i,1,n)
            cin>>b[i];
        sort(b+1,b+n+1);
        in(m);
        For(i,1,m)
            cin>>a[i].r>>a[i].t;
        For(i,1,m){
            if(a[i].t>b[n]||a[i].t<b[1]){
                L=n;R=1;
                temp=a[i].t;num=0;
                    while(temp*k<a[i].r){
                    temp+=2.0*PI;
                    num++;
                }
                if(a[i].t<b[L]&&num==0){
                    if(!vis[L][R][num]){
                        flag=1;
                        ans+=S(0,b[R]);
                        vis[L][R][num]=1;
                    }
                    continue;
                }
                if(a[i].t<b[L])
                    num--;
                if(num==0||n==1){
                    if(!vis[L][R][num]){
                        ans+=S(b[L],b[R]+2.0*PI);
                        vis[L][R][num]=1;
                    }
                }
                else{
                    if(!vis[L][R][num]){
                        ans+=S(b[L]+2.0*PI*(double)num,b[R]+2.0*PI*(double)num+2.0*PI)-S(b[L]+2.0*PI*(double)(num-1),b[R]+2.0*PI*(double)num);
                        vis[L][R][num]=1;
                    }
                }
            }
            else{
                R=upper_bound(b+1,b+n+1,a[i].t)-b;
                L=R-1;
                temp=a[i].t;num=0;
                    while(temp*k<a[i].r){
                    temp+=2.0*PI;
                    num++;
                }
                if(num==0){
                    if(!vis[L][R][num]){
                        ans+=S(b[L],b[R]);
                        vis[L][R][num]=1;
                    }
                }
                else{
                    if(!vis[L][R][num]){
                        ans+=S(b[L]+2.0*PI*(double)num,b[R]+2.0*PI*(double)num)-S(b[L]+2.0*PI*(double)(num-1),b[R]+2.0*PI*(double)(num-1));
                        vis[L][R][num]=1;
                    }
                }
            }
        }
        ans/=10.0;
        if(n==0)
            cout<<"Spiral "<<++cnt<<": -1"<<endl;
        else
            printf("Spiral %d: %.4f liters\n",++cnt,ans);
    }
    return 0;
}

 

posted @ 2019-08-18 11:50  WeiAR  阅读(342)  评论(0编辑  收藏  举报