drools规则的入门使用

1:pom文件

 

<!--drools-->
<dependency>
<groupId>org.drools</groupId>
<artifactId>drools-compiler</artifactId>
<version>7.10.0.Final</version>
</dependency>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>4.12</version>
</dependency>

2.新建 kmodule.xml

路径 resources\META-INF\kmodule.xml

<?xml version="1.0" encoding="UTF-8"?>
<kmodule xmlns="http://www.drools.org/xsd/kmodule">
<kbase name="rules">
<ksession name="all-rules"/>
</kbase>
</kmodule>

3.drl 文件
路径 resources\rules\test.drl

import com.example.serviceorder.vo.Person

dialect "mvel"

rule "age"
when
$person : Person(name=='小明')
then
$person.setAge(11);
System.out.println("我叫:"+$person.getName()+",现在:"+$person.getAge()+"岁");
end

rule "age1"
when
$person : Person(name=='小黑')
then
$person.setAge(13);
System.out.println("我叫:"+$person.getName()+",现在:"+$person.getAge()+"岁");
end

rule "age2"
when
$person : Person(name=='小白')
then
$person.setAge(14);
System.out.println("我叫:"+$person.getName()+",现在:"+$person.getAge()+"岁");
end
4. 实体
package com.example.serviceorder.vo;

/**
* @author lwq
* @date 2022/6/5 21:38
* @desciption: 测试
*/
public class Person {

private String name;
private int age;

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public int getAge() {
return age;
}

public void setAge(int age) {
this.age = age;
}
}

5.测试类

private static KieContainer container = null;
private KieSession statefulKieSession = null;

@Test
public void test111() {

KieServices kieServices = KieServices.Factory.get();
container = kieServices.getKieClasspathContainer();
statefulKieSession = container.newKieSession("all-rules");
Person person = new Person();


person.setName("小白");

statefulKieSession.insert(person);
statefulKieSession.fireAllRules();
statefulKieSession.dispose();
  System.out.println(JSON.toJSON(person));

}
6.打印结果
{"name":"小白","age":14}

7.动态加载规则工具类

package com.example.serviceorder.util;

import org.kie.api.KieServices;
import org.kie.api.builder.KieBuilder;
import org.kie.api.builder.KieFileSystem;
import org.kie.api.builder.KieRepository;
import org.kie.api.runtime.KieContainer;
import org.kie.api.runtime.KieSession;

/**
* @author lwq
* @date 2022/6/5 22:02
* @desciption: Drools工具类
*/
public class DroolsUtil {
private static KieContainer container = null;

public static <T> T execute(T t, String rule) {

container = load(rule);
KieSession kieSession = container.newKieSession();
kieSession.insert(t);
kieSession.fireAllRules();
kieSession.dispose();
return t;
}


private static KieContainer load(String rule) {

KieServices kieServices = KieServices.Factory.get();
KieRepository repository = kieServices.getRepository();

KieFileSystem kieFileSystem = kieServices.newKieFileSystem();
kieFileSystem.write("src/main/resources/rules" + "test.drl", rule);
KieBuilder kieBuilder = kieServices.newKieBuilder(kieFileSystem);
kieBuilder.buildAll();

return kieServices.newKieContainer(repository.getDefaultReleaseId());

}
}
8.测试动态加载规则工具类
@Test
public void test1112() {
//rule 规则可以存在数据库一个字段里面 oracle 数据库可以使用 clob 类型
//mysql 数据库可以使用 longtext类型
//也可以放到 redis 里面
    String rule="\n" +
"import com.example.serviceorder.vo.Person\n" +
"\n" +
"dialect \"mvel\"\n" +
"\n" +
"rule \"age\"\n" +
" when\n" +
" $person : Person(name=='小明')\n" +
" then\n" +
" $person.setAge(11);\n" +
" System.out.println(\"我叫:\"+$person.getName()+\",现在:\"+$person.getAge()+\"岁\");\n" +
"end\n" +
"\n" +
"rule \"age1\"\n" +
" when\n" +
" $person : Person(name=='小黑')\n" +
" then\n" +
" $person.setAge(13);\n" +
" System.out.println(\"我叫:\"+$person.getName()+\",现在:\"+$person.getAge()+\"岁\");\n" +
"end\n" +
"\n" +
"rule \"age2\"\n" +
" when\n" +
" $person : Person(name=='小白')\n" +
" then\n" +
" $person.setAge(14);\n" +
" System.out.println(\"我叫:\"+$person.getName()+\",现在:\"+$person.getAge()+\"岁\");\n" +
"end";

Person person = new Person();


person.setName("小明");


DroolsUtil.execute(person, rule);

System.out.println(JSON.toJSON(person));
}

6.打印结果
{"name":"小明","age":11}




 
posted @ 2022-06-05 22:45  黑狗已醒  阅读(330)  评论(0编辑  收藏  举报