摘要: -- abs函数 select * from A a inner join B b on a.CODE = b.CODE where a.NAME = '市本级' and abs(a.PROGRAM_BUDGET - b.money) >= 100 阅读全文
posted @ 2021-03-18 10:32 万里哥 阅读(475) 评论(0) 推荐(0) 编辑