lambda表达式
lambda表达式有个限制,那就是只能引用 final 或 final 局部变量,这就是说不能在lambda内部修改定义在域外的变量。
Compile
time
error :
local variables referenced from a lambda expression must be final or effectively final
1,List转Map//针对重复key的 覆盖之前的value
List<Person> list = new ArrayList<>(); Map<String, Person> map2 = list.stream().filter(e->StringUtil.isNotBlank(e.getName())).collect(Collectors.toMap(Person::getName , (p) -> p,(k,v)->v)); //value为空,直接存放 不调用map.merge Map<String, String> map3 = list.stream().collect(Collector.of(HashMap::new, (m,per)->m.put(per.getName(),per.getSex()), (k,v)->v, Characteristics.IDENTITY_FINISH));
Map<Integer, List<Apple>> groupBy = appleList.stream().collect(Collectors.groupingBy(Apple::getId));
2,List转List
List<String> userIdList = Lists.newArrayList(); List<SubUserVO> subUserVOList = new ArrayList<>(); subUserVOList.forEach(e -> userIdList.add(e.getId()));
List<CluePoolDO> search = new ArrayList<>();
List<Long> clueIds = search.stream().map(CluePoolDO::getId).collect(Collectors.toList());
3,条件过滤
List<String> strList = new ArrayList<>(); List<String> filtered = strList.stream().filter(x -> x.length()> 2).collect(Collectors.toList());
ArrayList<String> httpStrsTmp=new ArrayList<>(); if(httpStrsTmp.stream().filter(f->f.equals("x")).count()<=0){ //xxxxxx }
4,List转拼接字符串
List<String> G7 = Arrays.asList("USA", "Japan", "France", "Germany", "Italy", "U.K.","Canada"); String G7Countries = G7.stream().map(x -> x.toUpperCase()).collect(Collectors.joining(", "));
5,List的最大,小,求和,平均值计算
List<Integer> primes = Arrays.asList(2, 3, 5, 7, 11, 13, 17, 19, 23, 29); IntSummaryStatistics stats = primes.stream().mapToInt((x) -> x).summaryStatistics(); System.out.println("最大值 : " + stats.getMax()); System.out.println("最小值 : " + stats.getMin()); System.out.println("总 和 : " + stats.getSum()); System.out.println("平均值 : " + stats.getAverage());
6,List迭代
List<OrderItem> itemList = new ArrayList<>(); itemList.stream().forEach(item -> { System.out.println(item.getId()); });
List features = Arrays.asList("Lambdas", "Default Method", "Stream API", "Date and Time API"); features.forEach(n -> System.out.println(n)); 或者 features.forEach(System.out::println);
7,List去重
List<String> originList = new ArrayList<>(); originList = originList.stream().distinct().collect(Collectors.toList());
// 将评论时间按照倒序排列后再放入 List<FbCommentVO> comments = fbPosts.getComments(); if (!CollectionUtils.isEmpty(comments)) { comments.sort(Comparator.comparing(FbCommentVO::getCommentTime).reversed()); }
8,排序(reversed反转)
List<Human> humans = Lists.newArrayList(new Human("Sarah", 12), new Human("Sarah", 10), new Human("Zack", 12)); humans.sort(Comparator.comparing(Human::getName).thenComparing(Human::getAge).reversed());
List<ShopSellerMenuVO> collect = list.stream().sorted(Comparator.comparing(ShopSellerMenuVO::getId)).collect(Collectors.toList());
9,获取list最大、最小的一条
List<Date> list = new ArrayList(); Date maxDate = list.stream().max((o1,o2) -> o1.compareTo(o2)).get(); Date minDate = list.stream().min((o1,o2) -> o1.compareTo(o2)).get(); List<Employee> userList = new ArrayList(); Employee max = userList.stream().max(Comparator.comparingInt(Employee ::getAge)).get(); Employee min= userList.stream().min(Comparator.comparingInt(Employee ::getAge)).get(); //注意空指针,对年龄判空
10,移动集合中元素的位置
Collections.swap(list,fromIndex,toIndex);
11,分组
productSpecNumsList.stream().collect(groupingBy(ProductSpecNums::getSpecId));