HDU 2049

#include<stdio.h>
long long int a[21];
long long int fun(int n,int m)
{
    int i;
    long long int sum = 1;
    m = m>(n-m)?n-m:m;
    for(i = 1; i <= m; i ++)
        sum = (sum*(n-m+i))/i;
    return sum;
}

int main()
{
    int i,T,n,m;
    a[2] = 1;
    a[3] = 2;
    for(i = 4;i <= 20;i++)
        a[i] = (i-1)*(a[i-1]+a[i-2]);
    scanf("%d",&T);
    while(T--)
    {
        scanf("%d%d",&n,&m);
        printf("%I64d\n",a[m]*fun(n,n-m));
    }
    return 0;
}


posted on 2014-04-30 18:34  wangzhili  阅读(65)  评论(0编辑  收藏  举报