HDU 2602

思路:简单的动态规划,0-1背包问题


#include<stdio.h>
#include<string.h>
int a[1001][1001],va[1001],vo[1001];
int max(int x, int y)
{
    return x>y?x:y;
}

int main()
{
    int T,i,j,n,v;
    scanf("%d",&T);
    while(T--)
    {
        memset(a,0,sizeof(a));
        scanf("%d%d",&n,&v);
        for(i = 0;i < n;i ++)
            scanf("%d",&va[i]);
        for(i = 0;i < n;i ++)
            scanf("%d",&vo[i]);
        for(i = 0;i <= v;i ++)
        {
            for(j = 0;j < n;j ++)
            {
                if(i>=vo[j])
                    a[i][j] = max(a[i][j-1],a[i-vo[j]][j-1]+va[j]);
                else
                    a[i][j] = a[i][j-1];
            }
        }
        printf("%d\n",a[v][n-1]);
    }
}
#include<stdio.h>
#include<string.h>
int a[1001],va[1001],vo[1001];
int max(int x, int y)
{
    return x>y?x:y;
}

int main()
{
    int T,i,j,n,v;
    scanf("%d",&T);
    while(T--)
    {
        memset(a,0,sizeof(a));
        scanf("%d%d",&n,&v);
        for(i = 1;i <= n;i ++)
            scanf("%d",&va[i]);
        for(i = 1;i <= n;i ++)
            scanf("%d",&vo[i]);
        for(i = 1;i <= n;i ++)
        {
            for(j = v;j >= 0;j --)
            {
                if(j>=vo[i])
                    a[j] = max(a[j],a[j-vo[i]]+va[i]);
                else
                    a[j] = a[j];
            }
        }
        printf("%d\n",a[v]);
    }
}



posted on 2014-04-30 18:34  wangzhili  阅读(89)  评论(0编辑  收藏  举报